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  • 【LG3231】[HNOI2013]消毒

    题面

    洛谷

    题解

    img

    代码

    (100pts)

    #include<iostream>
    #include<cstdio>
    #include<cstdlib>
    #include<cstring> 
    #include<cmath> 
    #include<algorithm>
    using namespace std;
    inline int gi() {
    	register int data = 0, w = 1;
    	register char ch = 0;
    	while (!isdigit(ch) && ch != '-') ch = getchar();
    	if (ch == '-') w = -1, ch = getchar();
    	while (isdigit(ch)) data = 10 * data + ch - '0', ch = getchar();
    	return data * w; 
    }
    #define MAX_N 5005 
    struct Graph { int to, next; } e[MAX_N * 10]; int fir[MAX_N], e_cnt;
    void clearGraph() { memset(fir, -1, sizeof(fir)); e_cnt = 0; }
    void Add_Edge(int u, int v) { e[e_cnt] = (Graph){v, fir[u]}; fir[u] = e_cnt++; }
    int A, B, C; 
    int tot, xx[MAX_N], yy[MAX_N], zz[MAX_N];
    int vis[MAX_N], dep, match[MAX_N];
    bool dfs(int x) {
        for (int i = fir[x]; ~i; i = e[i].next) {
            int v = e[i].to;
            if (dep != vis[v]) {
                vis[v] = dep;
                if (!match[v] || dfs(match[v])) {
                    match[v] = x; 
                    return true;
                }
            }
        }
        return false;
    }
    int main() {
    	int T = gi();
    	int a, b, c, pos; 
    	while (T--) {
    		tot = 0; 
    		a = gi(), b = gi(), c = gi(), pos = 1;
    		if (b < a && b < c) pos = 2; else if (c < a && c < b) pos = 3;
    		for (int i = 1; i <= a; i++)
    			for (int j = 1; j <= b; j++)
    				for (int k = 1; k <= c; k++) { 
    					int x = gi(); 
    					if (!x) continue; 
    					else if (pos==1) ++tot, zz[tot]=i, xx[tot] = j, yy[tot] = k; 
                        else if (pos==2) ++tot, zz[tot]=j, xx[tot] = i, yy[tot] = k; 
                        else if (pos==3) ++tot, zz[tot]=k, xx[tot] = j, yy[tot] = i; 
    				}
    		A = a, B = b, C = c;
    		if (pos == 2) swap(A, B); 
            if (pos == 3) swap(A, C);
    		int ans = 1e9; 
    		for (int i = 0, sum; i < (1 << A); i++) {
    			for (int j = 1; j <= B; j++) match[j] = 0, fir[j] = -1;
    			e_cnt = 0; 
    			sum = A;
    			for (int j = i; j; j -= (j & -j)) --sum;
    			for (int j = 1; j <= tot; j++)
    				if ((1 << (zz[j] - 1)) & i) Add_Edge(xx[j], yy[j]); 
    	    	for (int j = 1; j <= B; j++) {
    		    	++dep;
    		    	if (dfs(j)) ++sum;
    		    	if (sum >= ans) break; 
    		    } 
    		    ans = min(ans, sum); 
    		}
    		printf("%d
    ", ans); 
    	} 
    	return 0; 
    } 
    
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  • 原文地址:https://www.cnblogs.com/heyujun/p/10404959.html
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