LeetCode 125. Valid Palindorme (验证回文字符串)

Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

For example,
"A man, a plan, a canal: Panama" is a palindrome.
"race a car" is not a palindrome.

Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.

For the purpose of this problem, we define empty string as valid palindrome.

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题目标签：String， Two Pointers

　　题目给了我们一个string s， 让我们判断它是不是 palindorme。

　　对于s， 我们只需要比较 字母 和 数字。

       设置一个 left = 0， right = s.length() -1，依次比较，其中遇到任何其他 char 就跳过，具体看code。

　　一开始不知道有 Character.isLetterOrDigit() ，还分别用了 letter 和 digit - -

Java Solution:

Runtime beats 80.01% 

完成日期：03/07/2017

关键词：two pointers

关键点：skip all non-alphanumeric chars

class Solution 
{
    public boolean isPalindrome(String s) 
    {
        // use two pointers
        int left = 0;
        int right = s.length() - 1;
        
        char [] char_arr = s.toCharArray();
        
        while(left < right)
        {
            while(left < right && !Character.isLetterOrDigit(char_arr[left])) // if char is not letter or digit
                left++;
            
            while(left < right && !Character.isLetterOrDigit(char_arr[right])) // if char is not letter or digit
                right--;

            if(Character.toUpperCase(char_arr[left]) != Character.toUpperCase(char_arr[right]))
                return false;
            
            left++;
            right--;
        }
        
        return true;
    }
    

}

参考资料：n/a

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