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  • 616. Add Bold Tag in String

    package LeetCode_616
    
    import java.util.*
    import kotlin.collections.HashSet
    
    /**
     * 616. Add Bold Tag in String
     * (Prime)
     * Given a string s and a list of strings dict,
     * you need to add a closed pair of bold tag <b> and </b> to wrap the substrings in s that exist in dict.
     * If two such substrings overlap, you need to wrap them together by only one pair of closed bold tag.
     * Also, if two substrings wrapped by bold tags are consecutive, you need to combine them.
     *
    Example 1:
    Input:
    s = "abcxyz123"
    dict = ["abc","123"]
    Output:
    "<b>abc</b>xyz<b>123</b>"
    
    Example 2:
    Input:
    s = "aaabbcc"
    dict = ["aaa","aab","bc"]
    Output:
    "<b>aaabbc</b>c"
    
    Note:
    1. The given dict won't contain duplicates, and its length won't exceed 100.
    2. All the strings in input have length in range [1, 1000].
     * */
    class Solution {
        /*
        * solution: use array to record current latter if need bold;
        * Time complexity:O(n^3), Space complexity:O(n+d)
        * n=s.length
        * d=words.size
        * */
        fun addBoldTag(words: List<String>, s: String): String {
            val set = HashSet<String>()
            set.addAll(words)
            val n = s.length
            //1 represent need bold
            val bolded = IntArray(n)
    
            /*checking each sub-string
                * for example: aabcd, checking order like:
                * 1. a,aa,aab,aabc,aabcd
                * 2. a,ab,abc,abcd
                * 3. b,bc,bcd
                * 4. c,cd,d
                * */
            for (i in 0 until n) {
                for (j in 1 .. n - i) {
                    if (set.contains(s.substring(i, i+j))) {
                        //0,1,1,1,0,
                        Arrays.fill(bolded, i, i + j, 1)
                    }
                }
            }
            bolded.forEach { print("$it,") }
    
            //set the result by boled array
            val sb = StringBuilder()
            for (i in 0 until n) {
                if (bolded[i] == 1 && (i == 0 || bolded[i - 1] != 1)) {
                    sb.append("<b>")
                }
                sb.append(s[i])
                //add </b> in the last, so check if(i==n-1)
                if (bolded[i] == 1 && (i == n - 1 || bolded[i + 1] != 1)) {
                    sb.append("</b>")
                }
            }
            println(sb.toString())
            return sb.toString()
        }
    }
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  • 原文地址:https://www.cnblogs.com/johnnyzhao/p/13634173.html
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