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  • 最大子序列(java版)

     1 package com.algorithm.test;
     2 /**
     3  * 最大子序列
     4  * @author LiFen
     5  *
     6  */
     7 public class LargestSubsequence {
     8     public static void main(String[] args) {
     9         int[] arr = {4,-3,5,-2,-1,2,6,-2};
    10         System.out.println(maxSubSum(arr));
    11         
    12         System.out.println(maxSumRec(arr, 0, arr.length - 1));
    13         
    14         System.out.println(maxSubSum2(arr));
    15     }
    16     
    17     /*
    18      * 时间复杂度O(N*N)
    19      */
    20     public static int maxSubSum(int [] a) {
    21         int maxSum = 0;
    22         
    23         for(int i = 0; i < a.length; i++) {
    24             int thisSum = 0;
    25             for(int j = 0; j < a.length; j++) {
    26                 
    27                 thisSum += a[j];
    28                 
    29                 if(thisSum > maxSum)
    30                     maxSum = thisSum;
    31             }
    32         }
    33         return maxSum;
    34     }
    35     /*
    36      * 递归
    37      * 时间复杂度O(N logN)
    38      */
    39     public static int maxSumRec(int [] a, int left, int right) {
    40         if(left == right) {
    41             if(a[left] > 0)
    42                 return a[left];
    43             else return 0;
    44         }
    45         
    46         int center = (left + right) / 2;
    47         int maxLeftSum = maxSumRec(a, left, center);
    48         int maxRightSum = maxSumRec(a, center + 1, right);
    49         
    50         int maxLeftBorderSum = 0,leftBorderSum = 0;
    51         for(int i = center; i >= left; i--) {
    52             leftBorderSum += a[i];
    53             if(leftBorderSum > maxLeftBorderSum)
    54                 maxLeftBorderSum = leftBorderSum;
    55         }
    56         
    57         int maxRightBorderSum = 0, rightBoderSum = 0;
    58         for(int i = center + 1; i <= right; i++) {
    59             rightBoderSum += a[i];
    60             if(rightBoderSum > maxRightBorderSum)
    61                 maxRightBorderSum = rightBoderSum;
    62         }
    63         return Math.max(Math.max(maxLeftSum, maxRightSum),maxLeftBorderSum + maxRightBorderSum);
    64     }
    65     /*
    66      * 联机算法
    67      * 快
    68      */
    69     public static int maxSubSum2(int [] a) {
    70         int maxSum = 0, thisSum = 0;
    71         
    72         for(int i = 0; i < a.length; i++) {
    73             thisSum += a[i];
    74             
    75             if(thisSum > maxSum) {
    76                 maxSum = thisSum;
    77             }else if(thisSum < 0){
    78                 thisSum = 0;
    79             }
    80         }
    81         return maxSum;
    82     }
    83 }
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  • 原文地址:https://www.cnblogs.com/jxust-jiege666/p/7875655.html
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