普利姆算法（加点法）求最小生成树
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function Node(value) {
this.value = value;
this.neighbor = [];
this.distance = [];
}
var nodeA = new Node("a");
var nodeB = new Node("b");
var nodeC = new Node("c");
var nodeD = new Node("d");
var nodeE = new Node("e");
var nodeF = new Node("f");
var nodeG = new Node("g");
var nodeH = new Node("h");
//存放所有节点的数组
var pointSet = [nodeA, nodeB, nodeC, nodeD, nodeE, nodeF, nodeG, nodeH];
var max = Number.POSITIVE_INFINITY; //无穷大
var distance = [ //点与点之间的距离
// a b c d e f g h
[0, 1, 2, max, max, max, max, max], //a
[1, 0, max, 3, max, 5, max, max], //b
[2, max, 0, 4, max, max, 7, max], //c
[max, 3, 4, 0, 6, max, max, max], //d
[max, max, max, 6, 0, 8, 9, max], //e
[max, 5, max, max, 8, 0, max, 10], //f
[max, max, 7, max, 9, max, 0, 11], //g
[max, max, max, max, max, 10, 11, 0] //h
];
//prim算法
function prim(pointSet, distance, start) {
var nowPointSet = [];
nowPointSet.push(start);//将开始节点放入已连接数组中
while (true) {
//通过已连接节点，找到和它们相连接开销最小的节点
var minDistanceNode = getMinDistanceNode(pointSet, distance, nowPointSet);
nowPointSet.push(minDistanceNode);//将开销最小的节点加入已连接数组中
if(nowPointSet.length == pointSet.length) break;//所有节点都连接，跳出循环
}
console.log(nowPointSet);
}
function getMinDistanceNode(pointSet, distance, nowPointSet) {
for (var i = 0; i < nowPointSet.length; i++) { //遍历已连接的点
var pointIndex = getIndex(nowPointSet[i].value);//获取已连接节点在pointSet中的索引值
var pointDistance = distance[pointIndex];//通过pointIndex找到该连接节点对应所有边的开销
var minDistance = max;//最小距离默认为max
var fromNode = null;//起始节点
var endNode = null;//终止节点
for (var j = 0; j < pointDistance.length; j++) { //遍历所有边的开销
if (nowPointSet.indexOf(pointSet[j]) < 0 && pointDistance[j] <
minDistance) { //最小距离连接的节点不能在nowPointSet中 && 要小于minDistance
minDistance = pointDistance[j];
fromNode = nowPointSet[i];
endNode = pointSet[j];
}
}
}
fromNode.neighbor.push(endNode);//起始节点 将开销最小的节点加入
fromNode.distance.push({//起始节点 将开销最小的节点的值和距离加入
from: fromNode.value,
to: endNode.value,
distance: minDistance
});
endNode.neighbor.push(fromNode);
endNode.distance.push({
from: fromNode.value,
to: endNode.value,
distance: minDistance
});
return endNode;//返回开销最小的节点
}
function getIndex(str) {//获取索引值
for (var i = 0; i < pointSet.length; i++) {
if (str == pointSet[i].value) {
return i;
}
}
return -1;
}
prim(pointSet, distance, pointSet[2]);
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