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  • 数据结构实验之查找三:树的种类统计(SDUT 3375)

    C:

    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    struct node
    {
        char data[30];
        struct node *lc;
        struct node *rc;
        int num;
    };
    char a[30];
    int n;
    struct node *creat(struct node *root)
    {
        if(root == NULL)
        {
            root = (struct node *)malloc(sizeof(struct node));
            root->lc = NULL;
            root->rc = NULL;
            root->num = 1;
            strcpy(root->data, a);
        }
        else
        {
            if(strcmp(a, root->data) == 0)
            {
                root->num++;
            }
            else if(strcmp(a, root->data) < 0)
            {
                root->lc = creat(root->lc);
            }
            else
            {
                root->rc = creat(root->rc);
            }
        }
        return root;
    };
    void fin(struct node *root)
    {
        if(root != NULL)
        {
            fin(root->lc);
            printf("%s %.2lf%%
    ", root->data, 1.0 * root->num * 100 / n);
            fin(root->rc);
        }
    }
    int main()
    {
        int i, j;
        int len;
        struct node *root;
        scanf("%d ", &n);
        root = NULL;
        for(i = 0; i < n; i++)
        {
            gets(a);
            len = strlen(a);
            for(j = 0; j < len; j++)
            {
                if(a[j] >= 'A' && a[j] <= 'Z')
                {
                    a[j] = a[j] + 32;
                }
            }
            root = creat(root);
        }
        fin(root);
        return 0;
    }
    
    
    
    
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  • 原文地址:https://www.cnblogs.com/lcchy/p/10139406.html
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