zoukankan      html  css  js  c++  java
  • HDU

    HDU - 4788
    Time Limit:1000MS   Memory Limit:32768KB   64bit IO Format:%I64d & %I64u

    []  [Go Back]  [Status]  

    Description

      Yesterday your dear cousin Coach Pang gave you a new 100MB hard disk drive (HDD) as a gift because you will get married next year.
      But you turned on your computer and the operating system (OS) told you the HDD is about 95MB. The 5MB of space is missing. It is known that the HDD manufacturers have a different capacity measurement. The manufacturers think 1 “kilo” is 1000 but the OS thinks that is 1024. There are several descriptions of the size of an HDD. They are byte, kilobyte, megabyte, gigabyte, terabyte, petabyte, exabyte, zetabyte and yottabyte. Each one equals a “kilo” of the previous one. For example 1 gigabyte is 1 “kilo” megabytes.
      Now you know the size of a hard disk represented by manufacturers and you want to calculate the percentage of the “missing part”.
     

    Input

      The first line contains an integer T, which indicates the number of test cases.
      For each test case, there is one line contains a string in format “number[unit]” where number is a positive integer within [1, 1000] and unit is the description of size which could be “B”, “KB”, “MB”, “GB”, “TB”, “PB”, “EB”, “ZB”, “YB” in short respectively.
     

    Output

      For each test case, output one line “Case #x: y”, where x is the case number (starting from 1) and y is the percentage of the “missing part”. The answer should be rounded to two digits after the decimal point.
     

    Sample Input

    2 100[MB] 1[B]
     

    Sample Output

    Case #1: 4.63% Case #2: 0.00%

    Hint

    思路:基本的区别是在第一位
    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    
    int n;
    char u[8];
    
    int main()
    {
    	while (scanf("%d", &n) != EOF) {
    		for (int cas = 1; cas <= n; cas++) {
    			scanf("%*d%s", u);
    			printf("Case #%d: ", cas);
    			if (u[1] == 'B')
    				printf("0.00");
    			else if (u[1] == 'K')
    				printf("2.34");
    			else if (u[1] == 'M')
    				printf("4.63");
    			else if (u[1] == 'G')
    				printf("6.87");
    			else if (u[1] == 'T')
    				printf("9.05");
    			else if (u[1] == 'P')
    				printf("11.18");
    			else if (u[1] == 'E')
    				printf("13.26");
    			else if (u[1] == 'Z')
    				printf("15.30");
    			else if (u[1] == 'Y')
    				printf("17.28");
    			printf("%%
    ");
    		}
    	}
    	return 0;
    }



查看全文
  • 相关阅读:
    远程诊断DoIP
    基于linux内核包过滤技术的应用网关
    Boost内存池使用与测试
    C++ 编程规范
    大象——Thinking in UML
    C++ 创建类时常考虑的问题
    SLIP—串行线路上传输数据报的非标准协议
    神秘的程序员——编程的乐趣
    Bad Smell (代码的坏味道)
    模式与软件架构——软件架构的非功能特征
  • 原文地址:https://www.cnblogs.com/ldxsuanfa/p/10488871.html
  • Copyright © 2011-2022 走看看