zoukankan      html  css  js  c++  java
  • The Last Practice

    http://acm.hdu.edu.cn/diy/contest_showproblem.php?pid=1008&cid=22619




    Problem Description

    Tomorrow is contest day, Are you all ready?
    We have been training for 45 days, and all guys must be tired.But , you are so lucky comparing with many excellent boys who have no chance to attend the Province-Final.

    Now, your task is relaxing yourself and making the last practice. I guess that at least there are 2 problems which are easier than this problem.
    what does this problem describe?
    Give you a positive integer, please split it to some prime numbers, and you can got it through sample input and sample output.

    Input

    Input file contains multiple test case, each case consists of a positive integer n(1<n<65536), one per line. a negative terminates the input, and it should not to be processed.

    Output

    For each test case you should output its factor as sample output (prime factor must come forth ascending ), there is a blank line between outputs.

    Sample Input

    60
    12
    -1

    Sample Output

    Case 1.
    2 2 3 1 5 1
    
    Case 2.
    2 2 3 1
    <div style='font-family:Times New Roman;font-size:14px;background-color:F4FBFF;border:#B7CBFF 1px dashed;padding:6px'><div style='font-family:Arial;font-weight:bold;color:#7CA9ED;border-bottom:#B7CBFF 1px dashed'><i>Hint</i></div>
    60=2^2*3^1*5^1
    </div>
    

    Author

    lcy

    Source

    杭电ACM集训队训练赛(IV)



    #include <iostream>
    using namespace std;


    int main()
    {
     int n,p=1;
     while(cin >> n)
     {
      if(n<0) break;
      if(p!=1) cout<<endl;
      cout << "Case " << p << "."<<endl;
      p++;
      int m=0,i=2;
      while(i<=n)
      {
       if(n%i==0)
       {
        m++;
        n/=i;
       }
       else if(m!=0)
       {
        cout <<i<<" "<<m<<" ";
        m = 0;
        i++;
       }
       else
       {
        m=0;
        i++;
       }
      }
      if(m!=0)
      {
       cout <<i<<" "<<m<<" ";
      }
      cout<<endl;
     }
     return 0;
    }

  • 相关阅读:
    C#成员设计建议
    基于任务的异步编程模式(TAP)的错误处理
    基于任务的异步编程模式(TAP)
    C#克隆
    C#操作excel打印
    父元素如何围住浮动子元素
    intellij idea创建第一个动态web项目
    Idea快捷键
    Python中列表的copy方法
    C++读取数量不定的数据
  • 原文地址:https://www.cnblogs.com/lengxia/p/4387882.html
Copyright © 2011-2022 走看看