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  • Mysql练习题(1)

    表名和字段
    ------------------------------------------------------------------------------
    –1.学生表
    Student(s_id,s_name,s_birth,s_sex) --学生编号,学生姓名, 出生年月,学生性别
    –2.课程表
    Course(c_id,c_name,t_id) – --课程编号, 课程名称, 教师编号额
    –3.教师表
    Teacher(t_id,t_name) --教师编号,教师姓名
    –4.成绩表
    Score(s_id,c_id,s_score) --学生编号,课程编号,分数


    测试数据
    ------------------------------------------------------------------------------
    --建表
    --学生表
    CREATE TABLE `Student`(
    `s_id` VARCHAR(20),
    `s_name` VARCHAR(20) NOT NULL DEFAULT '',
    `s_birth` VARCHAR(20) NOT NULL DEFAULT '',
    `s_sex` VARCHAR(10) NOT NULL DEFAULT '',
    PRIMARY KEY(`s_id`)
    );
    --课程表
    CREATE TABLE `Course`(
    `c_id` VARCHAR(20),
    `c_name` VARCHAR(20) NOT NULL DEFAULT '',
    `t_id` VARCHAR(20) NOT NULL,
    PRIMARY KEY(`c_id`)
    );
    --教师表
    CREATE TABLE `Teacher`(
    `t_id` VARCHAR(20),
    `t_name` VARCHAR(20) NOT NULL DEFAULT '',
    PRIMARY KEY(`t_id`)
    );
    --成绩表
    CREATE TABLE `Score`(
    `s_id` VARCHAR(20),
    `c_id` VARCHAR(20),
    `s_score` INT(3),
    PRIMARY KEY(`s_id`,`c_id`)
    );
    --插入学生表测试数据
    insert into Student values('01' , '赵雷' , '1990-01-01' , '男');
    insert into Student values('02' , '钱电' , '1990-12-21' , '男');
    insert into Student values('03' , '孙风' , '1990-05-20' , '男');
    insert into Student values('04' , '李云' , '1990-08-06' , '男');
    insert into Student values('05' , '周梅' , '1991-12-01' , '女');
    insert into Student values('06' , '吴兰' , '1992-03-01' , '女');
    insert into Student values('07' , '郑竹' , '1989-07-01' , '女');
    insert into Student values('08' , '王菊' , '1990-01-20' , '女');
    --课程表测试数据
    insert into Course values('01' , '语文' , '02');
    insert into Course values('02' , '数学' , '01');
    insert into Course values('03' , '英语' , '03');

    --教师表测试数据
    insert into Teacher values('01' , '张三');
    insert into Teacher values('02' , '李四');
    insert into Teacher values('03' , '王五');

    --成绩表测试数据
    insert into Score values('01' , '01' , 80);
    insert into Score values('01' , '02' , 90);
    insert into Score values('01' , '03' , 99);
    insert into Score values('02' , '01' , 70);
    insert into Score values('02' , '02' , 60);
    insert into Score values('02' , '03' , 80);
    insert into Score values('03' , '01' , 80);
    insert into Score values('03' , '02' , 80);
    insert into Score values('03' , '03' , 80);
    insert into Score values('04' , '01' , 50);
    insert into Score values('04' , '02' , 30);
    insert into Score values('04' , '03' , 20);
    insert into Score values('05' , '01' , 76);
    insert into Score values('05' , '02' , 87);
    insert into Score values('06' , '01' , 31);
    insert into Score values('06' , '03' , 34);
    insert into Score values('07' , '02' , 89);
    insert into Score values('07' , '03' , 98);
    ---------------------

    练习题
    ------------------------------------------------------------------------------
    -- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数
    select
    s1.*,
    s2.01_score,
    s2.02_score
    from
    student s1,
    (
    select t1.s_id as s_id,
    t1.s_score as 01_score,
    t2.s_score as 02_score
    from
    score t1,
    score t2
    where
    t1.s_id = t2.s_id
    and t1.c_id = '01'
    and t2.c_id = '02'
    and t1.s_score > t2.s_score ) s2
    where
    s1.s_id = s2.s_id;
    -- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数
    select
    s1.*,
    s2.01_score,
    s2.02_score
    from
    student s1,
    (
    select t1.s_id as s_id,
    t1.s_score as 01_score,
    t2.s_score as 02_score
    from
    score t1,
    score t2
    where
    t1.s_id = t2.s_id
    and t1.c_id = '01'
    and t2.c_id = '02'
    and t1.s_score < t2.s_score ) s2
    where
    s1.s_id = s2.s_id;
    -- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
    select
    t1.s_id,
    t2.s_name,
    avg(t1.s_score) as avg_score
    from
    score t1
    left join student t2 on
    t1.s_id = t2.s_id
    group by
    t1.s_id
    having
    avg(t1.s_score) >= 60;
    -- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
    -- (包括有成绩的和无成绩的)
    select
    t1.s_id,
    t2.s_name,
    avg(t1.s_score) as avg_score
    from
    score t1
    left join student t2 on
    t1.s_id = t2.s_id
    group by
    t1.s_id
    having
    avg(t1.s_score) < 60;
    -- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
    select
    t2.s_id,
    t2.s_name,
    count(t1.c_id) as sun_course,
    sum(t1.s_score) as sum_score
    from
    student t2
    left join score t1 on
    t1.s_id = t2.s_id
    group by
    t1.s_id;
    -- 6、查询"李"姓老师的数量
    select
    count(1)
    from
    teacher
    where
    t_name like '李%' ;
    -- 7、查询学过"张三"老师授课的同学的信息
    select
    t1.*
    from
    student t1,
    score t2
    where
    t1.s_id = t2.s_id
    and t2.c_id in (
    select c_id
    from
    course
    where
    t_id = (
    select t_id
    from
    teacher
    where
    t_name = '张三'));
    -- 8、查询没学过"张三"老师授课的同学的信息
    select
    *
    from
    student
    where
    s_id not in (
    select
    distinct s_id
    from
    score
    where
    c_id in (
    select t2.c_id
    from
    teacher t1,
    course t2
    where
    t1.t_id = t2.t_id
    and t1.t_name = '张三'));

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  • 原文地址:https://www.cnblogs.com/liangyan131/p/11629024.html
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