zoukankan      html  css  js  c++  java
  • hdu1036

    Average is not Fast Enough!

    Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
    Total Submission(s): 3336    Accepted Submission(s): 1306


    Problem Description
    A relay is a race for two or more teams of runners. Each member of a team runs one section of the race. Your task is to help to evaluate the results of a relay race. 

    You have to process several teams. For each team you are given a list with the running times for every section of the race. You are to compute the average time per kilometer over the whole distance. That's easy, isn't it? 
    So if you like the fun and challenge competing at this contest, perhaps you like a relay race, too. Students from Ulm participated e.g. at the "SOLA" relay in Zurich, Switzerland. For more information visit http://www.sola.asvz.ethz.ch/ after the contest is over.
     
    Input
    The first line of the input specifies the number of sections n followed by the total distance of the relay d in kilometers. You may safely assume that 1 <= n <= 20 and 0.0 < d < 200.0. Every following line gives information about one team: the team number t (an integer, right-justified in a field of width 3) is followed by the n results for each section, separated by a single space. These running times are given in the format "h:mm:ss" with integer numbers for the hours, minutes and seconds, respectively. In the special case of a runner being disqualified, the running time will be denoted by "-:--:--". Finally, the data on every line is terminated by a newline character. Input is terminated by EOF.
     
    Output
    For each team output exactly one line giving the team's number t right aligned in a field of width 3, and the average time for this team rounded to whole seconds in the format "m:ss". If at least one of the team's runners has been disqualified, output "-" instead. Adhere to the sample output for the exact format of presentation.
     
    Sample Input
    2 12.5
    5 0:23:21 0:25:01
    42 0:23:32 -:--:--
    7 0:33:20 0:41:35
     
    Sample Output
    5: 3:52 min/km
    42: - 7:6:00 min/km
     
     
    Source
     

    #include <iostream>
    #include<stdio.h>
    using namespace std;

    int main()
    {
        int f, n, i, a, sum, h, m, s;
        double d;
        char c[20], t[100];
        scanf("%d%lf", &n, &d);
        while (~scanf("%d", &a))
        {
            sum = f = 0;
            for (i=1;i<=n;++i)
            {
                scanf("%s", c);
                if (c[0] == '-') f = 1;
                sscanf(c, "%d:%d:%d", &h, &m, &s);
                sum += h*3600 + m*60 + s;
            }
            if (f)
            printf("%3d: - ", a);
            else
            {
                sum = int(sum/d + 0.5);
                printf("%3d: %d:%2.2d min/km ", a, sum/60, sum%60);
            }
        }
        return 0;
    }

  • 相关阅读:
    linux shell学习一点点
    【转】gcc中的-w -W和-Wall选项
    gcc 与 g++的区别
    javascript 时间格式(很方便的原生函数)
    js跳出循环的方法区别( break, continue, return ) 及 $.each 的(return true 和 return false)
    weex stream 方法封装
    数组遍历 map()、forEach() 及 字符串切割 split() / 字符串截取 slice()、substring()、substr()
    underscore.js 页面数据渲染
    mysql 安装与启动
    CSS3 animation(动画) 属性
  • 原文地址:https://www.cnblogs.com/lxm940130740/p/3330655.html
Copyright © 2011-2022 走看看