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  • [leetCode]Merge k Sorted Lists

    Merge k sorted linked lists and return it as one sorted list. Analyze and describe its complexity.

    外部排序的基础

     1 #include <iostream>
     2 #include<vector>
     3 using namespace std;
     4 
     5 struct ListNode {
     6     int val;
     7     ListNode *next;
     8     ListNode(int x) : val(x), next(NULL) {}
     9 };
    10 class Solution {
    11 public:
    12     static const int MAX = 9999;
    13     ListNode *mergeKLists(vector<ListNode *> &lists) {
    14         int listnum = checkListNum(lists);
    15         ListNode *head,*tail;
    16         head = tail = NULL;
    17         while(listnum){
    18             int index,min;
    19             min = MAX;
    20             index = 0;
    21             for(int i = 0; i < lists.size();i++){
    22                 if(lists[i] != NULL){
    23                     if(lists[i]->val < min){
    24                         min = lists[i]->val;
    25                         index = i;
    26                     }
    27                 }
    28             }
    29             if(head == NULL){
    30                 head = lists[index];
    31                 tail = head;
    32             }else{
    33                 tail->next = lists[index];
    34                 tail = tail->next;
    35             }
    36             lists[index] = lists[index]->next;
    37             tail->next = NULL;
    38             listnum = checkListNum(lists);
    39         }
    40         return head;
    41     }
    42     int checkListNum(vector<ListNode *> &lists){
    43         int num = 0;
    44         for(int i = 0; i < lists.size();i++){
    45             if(lists[i] != NULL) num++;
    46         }
    47         return num;
    48     }
    49 };
    艰难的成长
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  • 原文地址:https://www.cnblogs.com/marylins/p/3590328.html
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