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  • 1043. Is It a Binary Search Tree (25)

    the problem is from pat,which website is http://pat.zju.edu.cn/contests/pat-a-practise/1043

    and the source code is as followed.

    #include<iostream>
    #include<vector>
    #include<cstdio>
    
    using namespace std;
    int pos;
    
    struct cell
    {
        cell *lchild;
        cell *rchild;
        int c;
        cell()
        {
            lchild = rchild = NULL;
        }
    };
    
    void insert1(cell *&root,int x)
    {
        if (!root)
        {
            root = new cell;
            root->c = x;
        }
        else
        {
            if (x < root->c)
            {
                insert1(root->lchild,x);
            }
            else
                insert1(root->rchild,x);
        }
    }
    void insert2(cell *&root,int x)
    {
        if (!root)
        {
            root = new cell;
            root->c = x;
        }
        else
            if (x > root->c)
            {
                insert2(root->lchild, x);
            }
            else
                insert2(root->rchild, x);
    }
    void preOrder(cell *root,vector<int> &v)
    {
        v.push_back(root->c);
        if (root->lchild != NULL)
            preOrder(root->lchild,v);
        if (root->rchild != NULL)
            preOrder(root->rchild,v);
    }
    
    void postOrder(cell *root,vector<int> &v)
    {
        if (root->lchild != NULL)
            postOrder(root->lchild, v);
        if (root->rchild != NULL)
            postOrder(root->rchild, v);
        v.push_back(root->c);
    }
    
    
    int main()
    {
        int n;
        vector<int> v1,v2,v3,v;
        scanf("%d",&n);
        for (int i = 0; i < n; i++)
        {
            int x;
            scanf("%d",&x);
            v1.push_back(x);
        }
        cell *r = NULL;//THE root of bst
        cell *r1 = NULL;//the root of mirror of bst;
        for (int i = 0; i < n; i++)
        {
            insert1(r,v1[i]);
            insert2(r1,v1[i]);
        }
        preOrder(r,v2);//the preorder of bst
        preOrder(r1,v3);//the preorder of the mirror of bst
    
        if (v2 != v1 && v3 != v1)
        {
            printf("NO
    ");
            return 0;
        }
        else
        {
            printf("YES
    ");
            if (v2 == v1)
            {
                postOrder(r,v);
                for (int i = 0; i < n; i++)
                {
                    printf("%d%c",v[i], ((i - n + 1) ? ' ' : '
    '));//this type of presentation is fitted for the pattern of pat.
    
                }
            }
            else if(v3 == v1)
            {
                postOrder(r1,v);
                for (int i = 0; i < n; i++)  
                    printf("%d%c", v[i], ((i - n + 1) ? ' ' : '
    '));
            }
        }
        return 0;
    }

    i think what is the most important for the bst-like problem is build a bst. that’s the point.

    as long as the bst is built,then some trial things remains.

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  • 原文地址:https://www.cnblogs.com/maverick-fu/p/3967169.html
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