People in Mars represent the colors in their computers in a similar way as the Earth people. That is, a color is represented by a 6-digit number, where the first 2 digits are for Red, the middle 2 digits for Green, and the last 2 digits for Blue. The only difference is that they use radix 13 (0-9 and A-C) instead of 16. Now given a color in three decimal numbers (each between 0 and 168), you are supposed to output their Mars RGB values.
Input
Each input file contains one test case which occupies a line containing the three decimal color values.
Output
For each test case you should output the Mars RGB value in the following format: first output "#", then followed by a 6-digit number where all the English characters must be upper-cased. If a single color is only 1-digit long, you must print a "0" to the left.
Sample Input
15 43 71
Sample Output
#123456
题目大意:把10进制数转换为13进制数;
输出要求:以#开始用'A' 'B' 'C' 分别表示10 11 12 ;如果高位为0则填充0
1 #include<iostream> 2 using namespace std; 3 4 int main(){ 5 char dig[]={'0','1','2','3','4','5','6','7','8','9','A','B','C'}; 6 int r,g,b; 7 cin>>r>>g>>b; 8 printf("#%c%c%c%c%c%c%c",dig[r/13],dig[r%13],dig[g/13],dig[g%13],dig[b/13],dig[b%13]); 9 return 0; 10 }