zoukankan      html  css  js  c++  java
  • POJ 2774

    求两串的最长相同公共连续子串

    将两串拼接在一起,中间用一个未出现过的符号隔开

    求 sa, height

    sa[i] 与 sa[i-1] 不在同一个串时的 height[i] 的最大值就是答案

     1 #include <iostream>
     2 #include <cstdio>
     3 #include <cstring>
     4 using namespace std;
     5 const int MAXN = 200005;
     6 
     7 struct SuffixArray
     8 {
     9     int wa[MAXN], wb[MAXN], wsf[MAXN], wv[MAXN];
    10     int Cmp(int r[], int a, int b, int k)
    11     {
    12         return r[a] == r[b] && r[a+k] == r[b+k];
    13     }
    14     void GetSa(int r[], int sa[], int n, int m)
    15     {
    16         int i, j, p, *x = wa, *y = wb, *t;
    17         for (i = 0; i < m; i++) wsf[i] = 0;
    18         for (i = 0; i < n; i++) wsf[x[i]=r[i]]++;
    19         for (i = 1; i < m; i++) wsf[i] += wsf[i-1];
    20         for (i = n - 1; i >= 0; i--) sa[--wsf[x[i]]] = i;
    21         for (p = j = 1; p < n; j *= 2, m = p)
    22         {
    23             for (p = 0, i = n - j; i < n; i++) y[p++] = i;
    24             for (i = 0; i < n; i++) if(sa[i] >= j) y[p++] = sa[i] - j;
    25             for (i = 0; i < n; i++) wv[i] = x[y[i]];
    26             for (i = 0; i < m; i++) wsf[i] = 0;
    27             for (i = 0; i < n; i++) wsf[wv[i]]++;
    28             for (i = 1; i < m; i++) wsf[i] += wsf[i-1];
    29             for (i = n-1; i >= 0; i--) sa[--wsf[wv[i]]] = y[i];
    30             swap(x, y);
    31             x[sa[0]] = 0;
    32             for (p = i = 1; i < n; i++)
    33                 x[sa[i]] = Cmp(y, sa[i-1], sa[i], j) ? p - 1: p++;
    34         }
    35     }
    36     void GetHeight(int r[], int sa[], int rnk[], int height[], int n)
    37     {
    38         int i, j, k = 0;
    39         for (i = 1; i <= n; i++)
    40             rnk[sa[i]] = i;
    41         for (i = 0; i < n; i++)
    42         {
    43             if (k) k--;
    44             j = sa[rnk[i]-1];
    45             while (r[i+k] == r[j+k]) k++;
    46             height[rnk[i]] = k;
    47         }
    48     }
    49     
    50 }suffixArray;
    51 int r[MAXN], sa[MAXN], rnk[MAXN], height[MAXN];
    52 char s[MAXN];
    53 int len1, len2;
    54 bool check(int i, int j)
    55 {
    56     return ( sa[i] < len1 && sa[j] > len1 ) ||
    57            ( sa[i] > len1 && sa[j] < len1 ) ;
    58 }
    59 int main()
    60 {
    61     scanf("%s",s);
    62     len1 = strlen(s);
    63     s[len1] = '#';
    64     scanf("%s", s + len1 + 1);
    65     len2 = strlen(s);
    66     int m = 0;
    67     for (int i = 0; i < len2; i++)
    68     {
    69         if(i == len1) r[i] = 1;
    70         else r[i] = s[i] - 'a' + 2;
    71         m = max(r[i] + 1, m);
    72     }
    73     r[len2] = 0;
    74     suffixArray.GetSa(r, sa, len2 + 1, m);
    75     suffixArray.GetHeight(r, sa, rnk, height, len2);
    76     int ans = 0;
    77     for (int i = 1; i < len2; i++)
    78     {
    79         if(check(i,i-1))
    80         {
    81             ans = max(height[i], ans);
    82         }
    83     }
    84     printf("%d
    ", ans);
    85 }
    我自倾杯,君且随意
  • 相关阅读:
    bch算法生成nand flash中512byte校验和
    CFileDialog用法总结
    c++修改打印机名称
    c++连接打印机(转载)
    转发:for /f命令之—Delims和Tokens用法&总结
    c++中DLL文件的编写与实现——三步走
    GhostScript说明
    打印机API
    c++中DLL文件的编写与实现——三步走(2)
    windows程序设计基础知识
  • 原文地址:https://www.cnblogs.com/nicetomeetu/p/5750683.html
Copyright © 2011-2022 走看看