zoukankan      html  css  js  c++  java
  • 优先队列的基本用法(java和c++)

    #include <bits/stdc++.h>
    #define ll long long
    #define mod 1000000007
    using namespace std;
    //熟悉一下优先队列的基本用法
    int main()
    {
        int n;cin>>n;
        priority_queue<int>q;
        int j;
        for(int i=1;i<=n;i++)
        {
            cin>>j;
            q.push(j);
        }
        while(!q.empty())
        {
            cout<<q.top()<<endl;
            q.pop();
        }
        return 0;
    }
    

      java:

    import java.math.BigInteger;
    import java.util.*;
    
    public class CF470C {
    
        public static void main(String[] args) {
            PriorityQueue<String> queue = new PriorityQueue<String>();
            queue.add("C");
            queue.add("C++");
            queue.add("Python");
            queue.add("Java");
            // Printing the most priority element
            System.out.println("Head value using peek function:"
                                                  +queue.peek());
            // Printing all elements
            System.out.println("The queue elements");
            Iterator itr=queue.iterator();
            while(itr.hasNext())
                System.out.println(itr.next());
            // Removing the top priority element (or head) and
            // printing the modified pQueue
            queue.poll();
            System.out.println("After removing an element" +
                    "with poll function:");
            Iterator<String> itr2 = queue.iterator();
            while (itr2.hasNext())
                System.out.println(itr2.next());
            // // Removing Java
            queue.remove("C");
            System.out.println("after removing Java with" +
                    " remove function:");
            Iterator<String> itr3 = queue.iterator();
            while (itr3.hasNext())
                System.out.println(itr3.next());
            // // Check if an element is present
            boolean b=queue.contains("C");
            System.out.println ( "Priority queue contains C" +
                    "ot not?: " + b);
            // get objects from the queue in an array and
            // print the array
            Object[]arr=queue.toArray();
            System.out.println("Value in array: ");
            for(int i=0;i<arr.length;i++)
                System.out.println("Value: "+arr[i].toString());
    
    
        }
    }
    

      注意:Java中的优先队列没有排序功能,若要排序,请用:

    As you can see in the PriorityQueue javadoc: The Iterator provided in method iterator() is not guaranteed to traverse the elements of the priority queue in any particular order. If you need ordered traversal, consider using Arrays.sort(pq.toArray()). That's because java.util.PriorityQueue implements a binary heap.

    应用:

    Applications :
    Implementing Dijkstra’s and Prim’s algorithms.

    https://www.geeksforgeeks.org/priority-queue-class-in-java-2/

    例题:

    //��CF 947B
    #include<iostream>
    #include<cstdio>
    #include<fstream>
    #include<algorithm>
    #include<vector>
    #include<map>
    #include<set>
    #include<queue>
    #include<cmath>
    #include<cstring>
    #include<cstdlib>
    using namespace std;
    typedef long long LL;
    typedef double DB;
    const int N = 111111;
    int n,a[N],b[N];
    priority_queue<LL,vector<LL>,greater<LL> > Q;
    int main()
    {
    	int i,x;
    	LL w,ans;
    	scanf("%d",&n);
    	for(i=1;i<=n;i=i+1)
    		scanf("%d",a+i);
    	for(i=1;i<=n;i=i+1)
    		scanf("%d",b+i);
    	w=0,x=0;
    	for(i=1;i<=n;i=i+1){
    		ans=0;
    		Q.push(w+a[i]);
    		x++;
    		while(!Q.empty()&&Q.top()<=w+b[i]){
    			ans+=Q.top()-w;
    			Q.pop();
    			x--;
    		}
    		w+=b[i];
    		ans+=(LL)b[i]*x;
    		cout<<ans<<' ';
    	}
    	return 0;
    }
    

      

  • 相关阅读:
    ZOJ 2158 Truck History
    Knight Moves (zoj 1091 poj2243)BFS
    poj 1270 Following Orders
    poj 2935 Basic Wall Maze (BFS)
    Holedox Moving (zoj 1361 poj 1324)bfs
    ZOJ 1083 Frame Stacking
    zoj 2193 Window Pains
    hdu1412{A} + {B}
    hdu2031进制转换
    openjudge最长单词
  • 原文地址:https://www.cnblogs.com/passion-sky/p/8579566.html
Copyright © 2011-2022 走看看