Rightmost Digit
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 29108 Accepted Submission(s): 11115
Problem Description
Given a positive integer N, you should output the most right digit of N^N.
Input
The
input contains several test cases. The first line of the input is a
single integer T which is the number of test cases. T test cases follow.
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Each test case contains a single positive integer N(1<=N<=1,000,000,000).
Output
For each test case, you should output the rightmost digit of N^N.
Sample Input
2
3
4
Sample Output
7
6
Hint
In the first case, 3 * 3 * 3 = 27, so the rightmost digit is 7.
In the second case, 4 * 4 * 4 * 4 = 256, so the rightmost digit is 6.
Author
Ignatius.L
低位相乘与高位无关
import java.util.Scanner; public class Main { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner s = new Scanner(System.in); int t = s.nextInt(); for(int i=0; i<t; i++){ int n=s.nextInt(); int[][] a ={ {0},{1},{6,2,4,8}, {1,3,9,7}, {6,4}, {5}, {6}, {1,7,9,3}, {6,8,4,2}, {1,9} }; int[] l = {1,1,4,4,2,1,1,4,4,2}; int d = n%10; System.out.println(a[d][n%l[d]]); } } }