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  • java 获取输入的最小的以及第二小的数字

    //find nd smallest among n numbers
    
    import java.util.Scanner;
    
    public class Numbers {
    
        public static void main(String[] args) {
            int n, temp, min = Integer.MAX_VALUE, secondMin = Integer.MAX_VALUE;
            Scanner ip = new Scanner(System.in);
            System.out.print("Enter the number of inputs: ");
            n = ip.nextInt();
            for (int i = 1; i <= n; i++) {
                System.out.print("Enter number " + i + ": ");
                temp = ip.nextInt();
                if (temp <= min) {
                    secondMin = min;
                    min = temp;
                } else if (temp <= secondMin)
                    secondMin = temp;
            }
            System.out.println("The smallest number is " + min);
            System.out.println("The second smallest number is " + secondMin);
            ip.close();
        }
    
    }
    
    
    
    OUTPUT:
    Enter the number of inputs: 5
    Enter number 1: 3
    Enter number 2: 7
    Enter number 3: 2
    Enter number 4: 7
    Enter number 5: 1
    The smallest number is 1
    The second smallest number is 2
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  • 原文地址:https://www.cnblogs.com/sea-stream/p/12098776.html
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