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  • RCC 2014 Warmup (Div. 1)

    A

    暴力

     1 #include <iostream>
     2 #include<cstdio>
     3 #include<cstring>
     4 #include<algorithm>
     5 #include<stdlib.h>
     6 #include<vector>
     7 #include<cmath>
     8 #include<queue>
     9 #include<set>
    10 using namespace std;
    11 #define N 1010
    12 #define LL long long
    13 #define INF 0xfffffff
    14 const double eps = 1e-8;
    15 const double pi = acos(-1.0);
    16 const double inf = ~0u>>2;
    17 vector<int>ed[N];
    18 bool w[N][N];
    19 int main()
    20 {
    21     int i,j,n,m;
    22     int flag = 1;
    23     cin>>n>>m;
    24     for(i = 1; i <=  n;i++)
    25     {
    26         int k = 0;
    27         w[i][i] = 1;
    28         for(j = 1 ; j <= n ; j++)
    29         {
    30             if(!w[i][j])
    31             {
    32                 w[i][j] = 1;
    33                 w[j][i] = 1;
    34                 ed[i].push_back(j);
    35                 k++;
    36             }
    37             if(k==m) break;
    38         }
    39         if(k<m)
    40         {
    41             flag = 0;
    42             break;
    43         }
    44     }
    45     if(!flag) {puts("-1");return 0;}
    46     printf("%d
    ",n*m);
    47     for(i = 1; i <= n ;i++)
    48     {
    49         for(j = 0; j < ed[i].size(); j++)
    50         printf("%d %d
    ",i,ed[i][j]);
    51     }
    52     return 0;
    53 }
    View Code

    B 状压

    这个需要排下序,不然不能保证压的正确。

     1 #include <iostream>
     2 #include<cstdio>
     3 #include<cstring>
     4 #include<algorithm>
     5 #include<stdlib.h>
     6 #include<vector>
     7 #include<cmath>
     8 #include<queue>
     9 #include<set>
    10 using namespace std;
    11 #define N 1010
    12 #define LL long long
    13 //#define INF 1e18+1e12
    14 const double eps = 1e-8;
    15 const double pi = acos(-1.0);
    16 const double inf = ~0u>>2;
    17 const LL INF = (1ll<<62);
    18 LL dp[1<<20];
    19 struct node
    20 {
    21     int x,k,m;
    22     int a[105];
    23     int s;
    24 }p[105];
    25 bool cmp(node a,node b)
    26 {
    27     return a.k<b.k;
    28 }
    29 int main()
    30 {
    31     int i,j,n,m;
    32     LL b;
    33     cin>>n>>m>>b;
    34     for(i = 0 ; i < (1<<m) ; i++)
    35     dp[i] = INF;
    36     for(i = 1; i <= n ;i++)
    37     {
    38         p[i].s = 0 ;
    39         scanf("%d%d%d",&p[i].x,&p[i].k,&p[i].m);
    40         for(j = 0; j < p[i].m ; j++)
    41         {
    42             scanf("%d",&p[i].a[j]);
    43             p[i].s|=(1<<(p[i].a[j]-1));
    44         }
    45     }
    46     sort(p+1,p+n+1,cmp);
    47     dp[0] = 0;
    48     LL ans= INF;
    49     for(i = 1; i <= n ;i++)
    50     {
    51         for(j = 0 ;j < (1<<m) ; j++)
    52         {
    53             if(dp[j]==INF) continue;
    54             dp[j|p[i].s] = min(dp[j|p[i].s],dp[j]+p[i].x);
    55         }
    56         ans = min(ans,dp[(1<<m)-1]+p[i].k*b);
    57     }
    58     if(ans==INF)
    59     puts("-1");
    60     else
    61     cout<<ans<<endl;
    62     return 0;
    63 }
    View Code
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  • 原文地址:https://www.cnblogs.com/shangyu/p/3683062.html
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