[Swift]LeetCode1166.设计文件系统 | Design File System

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You are asked to design a file system which provides two functions:

• create(path, value): Creates a new path and associates a value to it if possible and returns True. Returns False if the path already exists or its parent path doesn't exist.
• get(path): Returns the value associated with a path or returns -1 if the path doesn't exist.

The format of a path is one or more concatenated strings of the form: / followed by one or more lowercase English letters. For example, /leetcode and /leetcode/problems are valid paths while an empty string and / are not.

Implement the two functions.

Please refer to the examples for clarifications. 

Example 1:

Input: 
["FileSystem","create","get"]
[[],["/a",1],["/a"]]
Output: 
[null,true,1]
Explanation: 
FileSystem fileSystem = new FileSystem();

fileSystem.create("/a", 1); // return true
fileSystem.get("/a"); // return 1

Example 2:

Input: 
["FileSystem","create","create","get","create","get"]
[[],["/leet",1],["/leet/code",2],["/leet/code"],["/c/d",1],["/c"]]
Output: 
[null,true,true,2,false,-1]
Explanation: 
FileSystem fileSystem = new FileSystem();

fileSystem.create("/leet", 1); // return true
fileSystem.create("/leet/code", 2); // return true
fileSystem.get("/leet/code"); // return 2
fileSystem.create("/c/d", 1); // return false because the parent path "/c" doesn't exist.
fileSystem.get("/c"); // return -1 because this path doesn't exist. 

Constraints:

• The number of calls to the two functions is less than or equal to 10^4 in total.
• 2 <= path.length <= 100
• 1 <= value <= 10^9

---

你需要设计一个能提供下面两个函数的文件系统：

• create(path, value): 创建一个新的路径，并尽可能将值 value 与路径 path 关联，然后返回 True。如果路径已经存在或者路径的父路径不存在，则返回 False。
• get(path): 返回与路径关联的值。如果路径不存在，则返回 -1。

“路径” 是由一个或多个符合下述格式的字符串连接起来形成的：在 / 后跟着一个或多个小写英文字母。

例如 /leetcode 和 /leetcode/problems 都是有效的路径，但空字符串和 / 不是有效的路径。

好了，接下来就请你来实现这两个函数吧！（请参考示例以获得更多信息）

示例 1：

输入： 
["FileSystem","create","get"]
[[],["/a",1],["/a"]]
输出： 
[null,true,1]
解释： 
FileSystem fileSystem = new FileSystem();

fileSystem.create("/a", 1); // 返回 true
fileSystem.get("/a"); // 返回 1

示例 2：

输入： 
["FileSystem","create","create","get","create","get"]
[[],["/leet",1],["/leet/code",2],["/leet/code"],["/c/d",1],["/c"]]
输出： 
[null,true,true,2,false,-1]
解释：
FileSystem fileSystem = new FileSystem();

fileSystem.create("/leet", 1); // 返回 true
fileSystem.create("/leet/code", 2); // 返回 true
fileSystem.get("/leet/code"); // 返回 2
fileSystem.create("/c/d", 1); // 返回 false 因为父路径 "/c" 不存在。
fileSystem.get("/c"); // 返回 -1 因为该路径不存在。 

提示：

• 对两个函数的调用次数加起来小于等于 10^4
• 2 <= path.length <= 100
• 1 <= value <= 10^9

---

2436 ms

class FileSystem {
    var root:Node

    init() {
        self.root = Node("",-1)        
    }
    
    func create(_ path: String, _ value: Int) -> Bool {
        if path.count <= 1 {return false}
        let split:[String] = path.components(separatedBy:"/")
        var curr:Node = root
        for i in 1..<split.count - 1
        {
            if curr.contents[split[i]] == nil
            {
                return false
            }
            curr = curr.contents[split[i]]!
        }
        var fileName:String = split.last!
        curr.contents[fileName] = Node(fileName, value)
        return true        
    }
    
    func get(_ path: String) -> Int {
        let split:[String] = path.components(separatedBy:"/")
        var curr:Node = root
        for i in 1..<split.count
        {
            if curr.contents[split[i]] == nil
            {
                return -1
            }
            curr = curr.contents[split[i]]!
        }
        return curr.val
    }
}

class Node
{
    var name:String
    var contents:[String:Node]
    var val:Int
    init(_ name:String,_ val:Int)
    {
        self.name = name
        self.contents = [String:Node]()
        self.val = val
    }
}

/**
 * Your FileSystem object will be instantiated and called as such:
 * let obj = FileSystem()
 * let ret_1: Bool = obj.create(path, value)
 * let ret_2: Int = obj.get(path)
 */