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  • hdu1016 Prime Ring Problem

    ......................

     1 #include <iostream>
     2 #include <string.h>
     3 #include <string>
     4 #include <queue>
     5 #include <algorithm>
     6 #include <cstdio>
     7 #include <cmath>
     8 using namespace std;
     9 bool vit[21];
    10 bool prim[10000];
    11 int n;
    12 bool isprim(int n){
    13     int i;
    14     for(i=2;i<=sqrt(n);++i){
    15         if(n%i==0) return false;
    16     }
    17     return true;
    18 }
    19 void init(){
    20     int i;
    21     for(i=2;i<10000;++i){
    22         if(isprim(i)==1) prim[i]=1;
    23         else             prim[i]=0;
    24     }
    25     return ;
    26 }
    27 
    28 void dfs(int step,string str){
    29 //    cout<<str<<endl;
    30     int i,j;
    31     int temp,begin;
    32     string t;
    33     if(step==n+1){
    34         printf("%d",str[0]-'a'+1);
    35         //cout<<str[0];
    36         for(i=1;i<str.length();++i){
    37         //    cout<<" "<<str[i];
    38             printf(" %d",str[i]-'a'+1);
    39         }
    40         printf("
    ");
    41         //cout<<endl;
    42         return ;
    43     }
    44     for(i=1;i<=n;++i){
    45         if(vit[i]==1) continue;
    46         t="0";
    47         t[0]=i+'a'-1;
    48         t=str+t;
    49         temp=t[step-2]-'a'+1;
    50         if(step==n&&prim[temp+i]==1&&prim[1+i]==1){
    51 //            cout<<"yeah!
    ";
    52             vit[i]=1;
    53             dfs(step+1,t);
    54             vit[i]=0;
    55         }else if(step!=n&&prim[temp+i]==1){
    56 //            cout<<"???"<<endl;
    57             vit[i]=1;
    58             dfs(step+1,t);
    59             vit[i]=0;
    60         }
    61     }
    62     return ;
    63 }
    64 int main(){
    65     int cnt=1;
    66     init();
    67 //    while(cin>>n)
    68 //        if(prim[n]==1) cout<<"yes"<<endl;
    69 //        else           cout<<"no"<<endl;
    70 //    while(cin>>n){
    71     while(~scanf("%d",&n)){
    72 //        cout<<"Case "<<cnt++<<":"<<endl;
    73         printf("Case %d:
    ",cnt++);
    74         vit[1]=1;
    75         dfs(2,"a");
    76 //        cout<<endl;
    77         printf("
    ");
    78     }
    79     return 0;
    80 }
    81         
    82 
    83         
    84 
    85             
    86         
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  • 原文地址:https://www.cnblogs.com/symons1992/p/3330643.html
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