效果图
1.在web.xml中加上如下配置.其实就是利用servlet的目录过滤,这样所有带有news的地址都会被拦截
一定要放在.actiobn下面，否则springmvc会无法找到对应的controller
1 <!-- restfull风格约定,去除前台超链接访问的后缀 -->
2 <servlet-mapping>
3 <servlet-name>DispatcherServlet</servlet-name>
4 <url-pattern>/news/*</url-pattern>
5 </servlet-mapping>
2.在springmvc.xml中配置视图解析器
1 <!-- 视图解析器(jsp)-->
2 <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
3 <!-- <property name="order" value="1"/> -->
4 <property name="prefix" value="/WEB-INF/"/>
5 <property name="suffix" value=".jsp"/>
6 </bean>
3.接下来在你的controller中加入一个方法,我以newsController为例,增加一个go方法用于超链接的跳转
1 /*前台超链接跳转处理*/ 2 @RequestMapping("/go/{name}") 3 public String go(@PathVariable String name) { 4 return name; 5 }
4.前台访问的地址
<li><a href="${pageContext.request.contextPath}/news/newsController/go/dataAnalysis">网站分析</a></li>
go后面传递的是页面的名称,这样即使我们传递dataAnalysis.html,只需要在上面的newsController的go方法中把后缀去掉,依然可以访问到正确的页面
(当然如果你用了拦截器自己放行就ok了)
拓展:首页的无后缀访问
首页是用户最先访问的一个页面,但我的首页不希望和普通的新闻页面一样带着news之类的字符串,实现方式也很简单
1.在web.xml中增加如下配置
1 <!-- 首页 -->
2 <servlet-mapping>
3 <servlet-name>IndexServlet</servlet-name>
4 <url-pattern>/index</url-pattern>
5 </servlet-mapping>
6
7 <!-- 后台 -->
8 <servlet-mapping>
9 <servlet-name>LoginServlet</servlet-name>
10 <url-pattern>/manage</url-pattern>
11 </servlet-mapping>
说明:创建servlet生成的是以下映射,上面是为了实现我们自定义的地址能够映射到我们的servlet上
1 <servlet-mapping>
2 <servlet-name>IndexServlet</servlet-name>
3 <url-pattern>/IndexServlet</url-pattern>
4 </servlet-mapping>
5 <servlet-mapping>
6 <servlet-name>LoginServlet</servlet-name>
7 <url-pattern>/LoginServlet</url-pattern>
8 </servlet-mapping>
2.创建servlet,在其中实现转发
1 public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
2 response.setContentType("text/html");
3 request.getRequestDispatcher("/WEB-INF/index.jsp").forward(request, response);
4 }
5
6 /**
7 * The doPost method of the servlet. <br>
8 *
9 * This method is called when a form has its tag value method equals to post.
10 *
11 * @param request the request send by the client to the server
12 * @param response the response send by the server to the client
13 * @throws ServletException if an error occurred
14 * @throws IOException if an error occurred
15 */
16 public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
17 doGet(request, response);
18 }
这样就ok了