Given two strings S~1~ and S~2~, S = S~1~ - S~2~ is defined to be the remaining string after taking all the characters in S~2~ from S~1~. Your task is simply to calculate S~1~ - S~2~ for any given strings. However, it might not be that simple to do it fast.
Input Specification:
Each input file contains one test case. Each case consists of two lines which gives S~1~ and S~2~, respectively. The string lengths of both strings are no more than 10^4^. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.
Output Specification:
For each test case, print S~1~ - S~2~ in one line.
Sample Input:
They are students.
aeiou
Sample Output:
Thy r stdnts.
#include<iostream> #include<string> using namespace std; const int maxn = 10010; bool hashTable[256]; string s1,s2; int main(){ getline(cin,s1); getline(cin,s2); int len1 = s1.length(),len2 = s2.length(); for(int i = 0 ; i < len2; i++){ hashTable[s2[i]] = true; } for(int i = 0; i < len1 ; i++){ if(hashTable[s1[i]] == false){ cout << s1[i]; } } return 0; }