zoukankan      html  css  js  c++  java
  • HDOJ 1391 Number Steps(打表DP)

    Problem Description
    Starting from point (0,0) on a plane, we have written all non-negative integers 0, 1, 2,… as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued.

    You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0…5000.

    Input
    The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.

    Output
    For each point in the input, write the number written at that point or write No Number if there is none.

    Sample Input
    3
    4 2
    6 6
    3 4

    Sample Output
    6
    12
    No Number

    不能直接开[5005][5005]的数组,这样内存不够。
    因为大部分数据没用,没列只有2个有效数据,所以开[5005][2]就可以了。

    import java.util.Scanner;
    
    public class Main{
        static int[][] db = new int[5005][2];
        public static void main(String[] args) {
            dabiao();
            Scanner sc = new Scanner(System.in);
            int t = sc.nextInt();
            while(t-->0){
                int x = sc.nextInt();
                int y = sc.nextInt();
                if(x==0&&y==0){
                    System.out.println(0);
                    continue;
                }
    
                if(x==1&&y!=1){
                    System.out.println("No Number");
                    continue;
                }
    
                if(x==1&&y==1){
                    System.out.println(1);
                    continue;
                }
    
                if(x==y||x==(y+2)){
                    if(x==(y+2)){
                        System.out.println(db[x][0]);
                    }else{
                        System.out.println(db[x][1]);
                    }
                }else{
                    System.out.println("No Number");
                }
            }
        }
    
        private static void dabiao() {
            int num=2;
            db[0][0]=0;
            boolean is = true;
            for(int i=2;i<=5003;i++){
                if(is){
                    db[i][0]=num;
                    num++;
                    db[i+1][0]=num;
                    num++;
                    is=!is;
                }else if(!is){
                    db[i-1][1]=num;
                    num++;
                    db[i][1]=num;
                    num++;
                    is=!is;
                }
            }
    //      System.out.println(db[2][0]);
    //      System.out.println(db[2][1]);
    //      System.out.println(db[3][0]);
    //      System.out.println(db[3][1]);
    //      System.out.println(db[4][0]);
    //      System.out.println(db[4][1]);
    //      System.out.println(db[5][0]);
    //      System.out.println(db[5][1]);
        }
    }
    
  • 相关阅读:
    使用python三方库xlrd解析excel数据
    testng之listener
    使用Junit实现批量运行
    gojs绘流程图
    sqlserver
    Android学习笔记之 android:collapseColumns ,android:shrinkColumns 和stretchColumns
    myBatis oracle 与mysql自增问题
    Oracle总结
    Oracle 树操作(select…start with…connect by…prior)
    Oracle 获取当前日期及日期格式
  • 原文地址:https://www.cnblogs.com/webmen/p/5739307.html
Copyright © 2011-2022 走看看