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  • 1385. Find the Distance Value Between Two Arrays

    Given two integer arrays arr1 and arr2, and the integer dreturn the distance value between the two arrays.

    The distance value is defined as the number of elements arr1[i] such that there is not any element arr2[j] where |arr1[i]-arr2[j]| <= d.

    Example 1:

    Input: arr1 = [4,5,8], arr2 = [10,9,1,8], d = 2
    Output: 2
    Explanation: 
    For arr1[0]=4 we have: 
    |4-10|=6 > d=2 
    |4-9|=5 > d=2 
    |4-1|=3 > d=2 
    |4-8|=4 > d=2 
    For arr1[1]=5 we have: 
    |5-10|=5 > d=2 
    |5-9|=4 > d=2 
    |5-1|=4 > d=2 
    |5-8|=3 > d=2
    For arr1[2]=8 we have:
    |8-10|=2 <= d=2
    |8-9|=1 <= d=2
    |8-1|=7 > d=2
    |8-8|=0 <= d=2
    

    Example 2:

    Input: arr1 = [1,4,2,3], arr2 = [-4,-3,6,10,20,30], d = 3
    Output: 2
    

    Example 3:

    Input: arr1 = [2,1,100,3], arr2 = [-5,-2,10,-3,7], d = 6
    Output: 1
    

    Constraints:

    • 1 <= arr1.length, arr2.length <= 500
    • -10^3 <= arr1[i], arr2[j] <= 10^3
    • 0 <= d <= 100
    class Solution {
        public int findTheDistanceValue(int[] arr1, int[] arr2, int d) {
            int l1 = arr1.length;
            int l2 = arr2.length;
            int res = 0;
            Arrays.sort(arr1);
            Arrays.sort(arr2);
            int tmp = 0;
            for(int i = 0; i < l1; i++){
                for(int j = l2-1; j >= 0; j--){
                    if(Math.abs(arr1[i] - arr2[j]) <= d){
                       break;  
                    }
                    else tmp++;
                }
                if(tmp == l2) res++;
                tmp = 0;
            }
            return res;
        }
    }
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  • 原文地址:https://www.cnblogs.com/wentiliangkaihua/p/12578954.html
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