topcoder 的一些输入输出格式

    自从上年的11月份参加过TC的比赛后，就再也没有参加了，因为它的输入输出格式比较难接受，还有它的页面字体比较小，看得我很辛苦...藉口藉口～～懒而已！不过以后我会尽量去参加的，为了提高自己的编程能力。

    以 SRM 144  DIV 2 的 200 分题目为例，记录下两种输入输出格式吧。

    

   

Problem Statement

    

Computers tend to store dates and times as single numbers which represent the number of seconds or milliseconds since a particular date. Your task in this problem is to write a method whatTime, which takes an int, seconds, representing the number of seconds since midnight on some day, and returns a string formatted as "<H>:<M>:<S>". Here, <H> represents the number of complete hours since midnight, <M> represents the number of complete minutes since the last complete hour ended, and <S> represents the number of seconds since the last complete minute ended. Each of <H>, <M>, and <S> should be an integer, with no extra leading 0's. Thus, if seconds is 0, you should return "0:0:0", while if seconds is 3661, you should return "1:1:1".

Definition

    

Class:	Time
Method:	whatTime
Parameters:	int
Returns:	string
Method signature:	string whatTime(int seconds)
(be sure your method is public)

 

Limits

    

Time limit (s):	2.000
Memory limit (MB):	64

 

Constraints

-

seconds will be between 0 and 24*60*60 - 1 = 86399, inclusive.

Examples

0)

 

    

0

 

Returns: "0:0:0"

 

 

1)

 

    

3661

 

Returns: "1:1:1"

 

 

2)

 

    

5436

 

Returns: "1:30:36"

 

 

3)

 

    

86399

 

Returns: "23:59:59"

 

    

   

JAVA 版

public class Time{

    public String whatTime(int seconds){

        int h = seconds / 3600;

        int m = (seconds % 3600) / 60;

        int s = seconds % 3600 - m * 60;

        return h + ":" + m + ":" + s;

    }

}

C++ 版

#include <iostream>

using namespace std;

class Time{

    public:

    string whatTime(int seconds)

    {

        int h = seconds / 3600;

        int m = (seconds % 3600) / 60;

        int s = seconds % 3600 - m * 60;

        char buf[40];

        sprintf(buf, "%d:%d:%d", h, m, s);

        return string(buf);

    }

};