zoukankan      html  css  js  c++  java
  • hdu2222Keywords Search

    Problem Description
    In the modern time, Search engine came into the life of everybody like Google, Baidu, etc. Wiskey also wants to bring this feature to his image retrieval system. Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched. To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
     
    Input
    First line will contain one integer means how many cases will follow by. Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000) Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50. The last line is the description, and the length will be not longer than 1000000.
     
    Output
    Print how many keywords are contained in the description.
     
    Sample Input
    1 5 she he say shr her yasherhs
     
    Sample Output
    3
     
    Author
    Wiskey
    #include<iostream>
    #include<cstring>
    #include<cstdio>
    #include<cmath>
    #include<queue>
    
    using namespace std;
    
    struct node
    {
        node* next[26];
        int end;
        node* fail;
        node()
        {
            for(int i = 0;i<26;i++)
                next[i] = NULL;
            fail = NULL;
            end = 0;
        }
    };
    node* root;
    char s[51],ss[1100000];
    void insert()
    {
        int i,l = strlen(s);
        node* k = root;
        for(i  = 0;i<l;i++)
        {
            int id = s[i]-'a';
            if(k->next[id] == NULL)
                k->next[id] = new node();
            k = k->next[id];
        }
        k->end++;
    }
    void build()
    {
        queue<node*> q;
        for(int i = 0;i<26;i++)
        {
            node* k = root;
            if(k->next[i] != NULL)
            {
                k->next[i]->fail = root;
                q.push(k->next[i]);
            }
        }
        while(!q.empty())
        {
            node*k = q.front();
            q.pop();
            for(int i = 0;i<26;i++)
            {
                if(k->next[i]!=NULL)
                {
                    node*t = k->fail;
                    while(t!=root&&t->next[i] == NULL) t = t->fail;
                    if(t->next[i] != NULL) t = t->next[i];
                    k->next[i]->fail = t;
                    q.push(k->next[i]);
                }
            }
        }
    }
    int ask()
    {
        int i,l = strlen(ss),ans = 0;
        node *k = root;
        for(i = 0;i<l;i++)
        {
            int id = ss[i]-'a';
            while(k!=root&&k->next[id] == NULL) k = k->fail;
            if(k->next[id]!=NULL) k = k->next[id];
            node* t = k;
            while(t!=root)
            {
                ans += t->end;
                t->end = 0;
                t = t->fail;
            }
        }
        return ans;
    }
    
    
    int main()
    {
        int z;
        int n,i,j,k;
        cin>>z;
        while(z--)
        {
            root = new node();
            scanf("%d",&n);
            while(n--)
            {
                scanf("%s",s);
                insert();
            }
            build();
            scanf("%s",ss);
            printf("%d
    ",ask());
        }
        return 0;
    }
  • 相关阅读:
    正则表达式的学习笔记
    apply()的使用
    for循环性能测试
    js基础复习~Array对象
    判断值是否为undefined
    layui 单选框取消选中
    layui 表单验证
    火狐浏览器下,表头边框无效
    css3 宽度百分比减去固定宽度 无效问题
    javaScript中的 call 和 apply
  • 原文地址:https://www.cnblogs.com/wos1239/p/4398942.html
Copyright © 2011-2022 走看看