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  • kExercise 5.4 Table of reciprocals, squares, cubes, and fourth powers.

    Exercise 5-4. Define a two-dimensional array, data[11][5] , of type double. Initialize
    the elements in the first column with values from 2.0 to 3.0 inclusive in steps of 0.1.
    If the first element in a row has value x, populate the remaining elements in each row
    with the values 1/x, x2, x3, and x4 . Output the values in the array with each row on a
    separate line and with a heading for each column.

    //Exercise 5.4 Table of reciprocals, squares, cubes, and fourth powers.
    #include <stdio.h>
    
    int main(void)
    {
      const size_t nrows = 11;              // Number of rows in the array
      const size_t ncols = 5;               // Number of columns in the array
      double data[nrows][ncols];            // Stores data values
      double value = 2.0;
      size_t row = 0 ;                 // Value to be stored in array
      size_t col = 0 ;
    
      for( row = 0 ; row < nrows ; ++row)
        {
        data[row][0] = value;
        data[row][1] = 1.0/data[row][0];               // 1/x
        data[row][2] = data[row][0]*data[row][0];      // x*x
        data[row][3] = data[row][2]*data[row][0];      // x*x*x
        data[row][4] = data[row][3]*data[row][0];      // x*x*x*x
            value += 0.1;
      }
    
    
      printf("            x  ");
      printf("          1/x  ");
      printf("          x*x  ");
      printf("         x*x*x ");
      printf("        x*x*x*x");
    
        for( row = 0 ; row < nrows ; ++row)
      {
        printf("
    ");
        for( col = 0 ; col < ncols ; ++col)
          printf("%15.4lf", data[row][col]);
      }
    
      printf("
    ");
        return 0;
    }

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  • 原文地址:https://www.cnblogs.com/xiaomi5320/p/4190246.html
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