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  • NYOJ 214 单调递增子序列(二)

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     1 #include<iostream>
     2 #include<cstdio>
     3 #include<memory.h>
     4 using namespace std;
     5 int a[100001],b[100001];
     6 
     7 int main()
     8 {
     9 //    freopen("in.txt","r",stdin);
    10     int n;
    11     memset(a,0,sizeof(a));
    12     memset(b,0,sizeof(b));
    13     while(scanf("%d",&n)!=EOF)
    14     {
    15         int i,j;
    16         scanf("%d",&a[0]);
    17         b[0] = a[0];
    18         for(i = 1,j = 1; i < n; ++i)
    19         {
    20             scanf("%d",&a[i]);
    21             if(a[i] > b[j-1])
    22                 b[j++] = a[i];
    23             else
    24             {
    25                 for(int k = 0; k < j; ++k)
    26                     if(a[i] < b[k])
    27                     {
    28                         b[k] = a[i];
    29                         break;
    30                     }
    31             }
    32         }
    33         printf("%d\n",j);
    34     }
    35     return 0;
    36 }
    37 
    38
    39 #include<cstdio>
    40 #include<algorithm>
    41 using namespace std;
    42 int num[100001];
    43 
    44 int main()
    45 {
    46 //    freopen("in.txt","r",stdin);
    47     int n,top;
    48     while(scanf("%d",&n)!=EOF)
    49     {
    50         scanf("%d",&num[0]);
    51         top = 1;
    52         for(int i = 1; i != n; ++i)
    53         {
    54             scanf("%d",&num[i]);
    55             int *p = lower_bound(num,num+top,num[i]);
    56             if(p-num == top) ++top;
    57             *p = num[i];
    58         }
    59         printf("%d\n",top);
    60     }
    61     return 0;
    62 }
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  • 原文地址:https://www.cnblogs.com/yaling/p/3034555.html
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