从数组中找出所有组合为s的数

java版本

package numCombine;
/**
 * 从数组中找出所有组合为s的数
 * @author root
 *
 */
public class NumComberAll {

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		int a[] = {2,3,3,2,2,4,1,4,-2,5,1};
		String b = "";
		fun(a, b, 11, 0, 5);
	}
	//递归搜索
	public static void fun(int a[],String b, int length, int  i, int s)
	{
		String temp = b;
		if(i>=length)
			return;
		//输出
		if(s==0)
			System.out.println(temp);
		//不取a[i]
		fun(a,temp, length, i+1, s);
		//取a[i]
		temp=temp+a[i];
		fun(a,temp, length, i+1, s-a[i]);
	}
}

C++版本

//递归搜索

void fun(int a[],string b, int length, int  i, int s)
{
	string temp = b;
	if(i>=length)
		return;
	//输出
	if(s==0)
		cout<<"complte"<<b<<endl;
	//不取a[i]
	fun(a,temp, length, i+1, s);
	//取a[i]
	stringstream ss;
	string str;
	ss<<a[i];
	ss>>str;
	temp.append(str);
	fun(a,temp, length, i+1, s-a[i]);
	
}

int main()
{
	int a[] = {2,3,3,2,2,4,1,4,-2,5,1};
	string b;
	fun(a, b, 11, 0, 5);	
	return 0;
}