"Contestant who earns a score equal to or greater than the k-th place finisher's score will advance to the next round, as long as the contestant earns a positive score..." — an excerpt from contest rules.
A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.
The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.
The second line contains n space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).
Output the number of participants who advance to the next round.
8 5
10 9 8 7 7 7 5 5
6
4 2
0 0 0 0
0
In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.
In the second example nobody got a positive score.
1 #include <iostream> 2 int n,k,i,j,a[51]; 3 using namespace std; 4 int main(){ 5 cin>>n>>k; 6 while(n>i) cin>>a[i++]; //不一样的输入方式 7 while (a[j]&&a[j]>=a[k-1]) ++j; 8 cout<<j; 9 }