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  • day01_final

    1、可以支持多个用户登录 (提示,通过字典存多个账户信息)。用户3次认证失败后,退出程序,

    #!/usr/bin/env python3
    
    dict = {
        'jack':{'pass':123,'count':0},
        'eray':{'pass':456,'count':0},
        'bike':{'pass':789,'count':0}
    }
    
    
    name = input ("plz input your name: ")
    print (dict[name]['pass'])
    
    if name not in dict:
        print ("Sorry,you input error.")
        exit()
    elif name in dict :
        print ("Ok,you input success.")
    
        while dict[name]['count'] < 3:
    
            pas = int(input("plz input your passwd: "))
    
            if pas == dict[name]['pass']:
                print ("Congratulation to you.")
                dict[name]['count'] = 3
            else:
                dict[name]['count'] += 1
    

    2、可以支持多个用户登录 (提示,通过列表存多个账户信息)

    用户3次认证失败后,退出程序,再次启动程序尝试登录时,还是锁定状态(提示:需把用户锁定的状态存到文件里)

    #!/usr/bin/env python3
    #-*- coding:utf-8 -*-
    #Author: Zhang Lei
    
    userdict = {"enven":111,"jack":222,"eray":333,"bike":444}
    count = 0
    num = 0
    
    while count < 3:
        username = input("What's your name? ")
        f = open("name.txt")
        date = f.readlines()
        date = ''.join(date).strip('\n')
        f.close()
    
        if username in date:
            print ("sorry,your account is blocked.")
            break
        else:
            if username not in userdict:
                print("no,you guess error...")
                count += 1
                continue
            elif username in userdict:
                print("year,input success...")
    
                while num < 3:
                    passwd = input("plz input your passwd:")
                    if passwd == str(userdict[username]):
                        print("Yes, congratulations to you...")
                        break
                    elif num == 2:
                        print("You are locked:", username)
                        f = open('name.txt','a+')
                        f.write(username +'\n')
                        f.close
                        break
                    else:
                        print("plz input your passwd again:")
                        num += 1
    
                break

     3、允许用户尝试3次, 每尝试3次后,如果还没猜对,就问用户是否还想继续玩,如果回答是Y 或y,则继续让其猜3次,一次往复,如果回答N或n,就退出程序,

    如果猜对了,就直接退出。

    #!/usr/bin/env python3
    # -*- coding:utf-8 -*-
    #Author: Zhang Lei
    
    count = 0
    user = "eray"
    
    while count < 3:
        name = input("Plz guess name: ")
        if user == name:
            print("Contratulations. You got it.")
            break
        elif count == 2:
            guess = input("Do you want to guess again?\nplz input y/n\n")
            if guess == "Y" or guess == "y":
                print ("Let's go run...")
                count = 0
                continue
            elif guess == "N" or guess =='n':
                print("Sorry,Your guess is stoped.")
                break
            else:
                print("you input error.")
                break
        else:
            print ("Sorry,You guess error.")
        count += 1
    

      

     上述例子采用标签的方式,如下:

    #!/usr/bin/env python3
    # -*- coding:utf-8 -*-
    #Author: Zhang Lei
    
    count = 0
    user = "eray"
    tag = True
    
    while tag:
        name = input("Plz guess name: ")
        if user == name:
            print("Contratulations. You got it.")
            tag = False
        elif count == 2:
            guess = input("Do you want to guess again?\nplz input y/n\n")
            while tag:
                if guess == "Y" or guess == "y":
                    print ("Let's go run...")
                    count = 0
                    break
                elif guess == "N" or guess =='n':
                    print("Sorry,Your guess is stoped.")
                    tag = False
                else:
                   print("you input error.")
                   tag = False
        else:
            print ("Sorry,You guess error.")
            count += 1
    

      

      

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  • 原文地址:https://www.cnblogs.com/zhangray/p/7119106.html
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