LeetCode7

7. 整数反转

int reverse(int x) {
    long long s=0;
    int k=x;
    while(k) {
        int m =k%10;
        k/=10;
        s = s*10+m;
    }
    if(s<INT_MIN || s> INT_MAX) {
        s=0;
    }
    s=(int)s;
    return s;
}