http://acm.hdu.edu.cn/showproblem.php?pid=2054
Problem Description
Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".
Input
each test case contains two numbers A and B.
Output
for each case, if A is equal to B, you should print "YES", or print "NO".
Sample Input
1 2
2 2
3 3
4 3
Sample Output
NO
YES
YES
NO
题解:不需要考虑前置零 把小数点后面多余的 0 去掉再进行比较就可以
代码:
#include <bits/stdc++.h> using namespace std; const int maxn=1e5+10; char a[maxn],b[maxn]; void rep(char s[]) { int len=strlen(s); int flag=0; for(int i=0;i<len;i++) { if(s[i]=='.') { flag=1; break; } } if(flag) { for(int i=len-1;i>=0;i--) { if(s[i]=='0') s[i]=' '; else break; len--; } if(s[len-1]=='.') s[len-1]=' '; } } int main() { while(~scanf("%s%s",a,b)) { rep(a); rep(b); if(strcmp(a,b)) printf("NO "); else printf("YES "); } return 0; }