import java.util.*;
class work7
{
public static void main(String[] args)
{//最多输入十亿位
String[] str = new String[]{"十位","百位","千位","万位","十万位","百万位","千万位","亿位","十亿位","百亿位","千亿位"};
System.out.println("请输入一个数字");
Scanner sac = new Scanner(System.in);
//接受用户输入的数
long sum = sac.nextInt();
long sum2=sum;
int a=0;
for (int i = 0 ; i<32 ;i++ )
{
//判断用户输入的数是几位数
if(sum/10>0){
sum=sum/10;
a++;
}else{
break;
}
}
if (sum2<10)
{
long k =sum;
System.out.println("这个数的只有个位是"+k);
}else{
//把用户输入的数是分解出来
for (int i = 0 ;i<=a ;i++ )
{
if (i==0)
{
long c = sum2%10;
System.out.println("这个数的个位是"+c);
}else if(i<a){
//这里要强转一下 这个函数出来的double;
long new1=(long)Math.pow( 10, i);
//参数说明：m为要求方的数，n为次方数
long b = sum2/new1%10;
System.out.println("这个数的第"+str[i-1]+"是"+b);
}else{
long new2= (long)Math.pow( 10, i);
long h = sum2/new2%10;
System.out.println("这个数的第"+str[i-1]+"是"+h);
}
}
}
}
}