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  • [React] Write Compound Components

    Compound component gives more rendering control to the user. The functionality of the component stays intact while how it looks and the order of the children can be changed at will. We get this functionality by using the special React.Children.map function to map over the children given to our <Toggle/> component. We map over the children to pass the on state as a prop to its children. We move the visual pieces of the component out into function components and add them as static properties to <Toggle/>.

    User has free control how On / Off / Button shows on the page:

        <Toggle onToggle={(on) => console.log("Toggle", on)}>
            <Toggle.On>
                Switch is On!
            </Toggle.On>
            <Toggle.Button />
            <Toggle.Off>
                Switch is Off!
            </Toggle.Off>
        </Toggle>;

    Toggle.On, Toggle.Off and Toggle.Button is private components for Toggle:

    class Toggle extends React.Component {
    
      // An empty function
      static defaultProps = {onToggle: () => {}};
      static On = ToggleOn;
      static Off = ToggleOff;
      static Button = ToggleButton;
    
      ....
    
    }

    All those components have props, which user doesn't need to care about, those props should be passed down fromt the parent component: Toggle:

    const ToggleOn = ({on, children}) => {
      if(on) {
        return (<div>{children}</div>)
      } else {
        return null;
      }
    };
    const ToggleOff = ({on, children}) => {
        if(on) {
            return null;
        } else {
            return (<div>{children}</div>);
        }
    };
    const ToggleButton = ({on, toggle, ...props}) => (
        <Switch on={on} onClick={toggle} {...props} />
    );

    This can be done by using React.Children.map and React.cloneElement:

      render() {
        const {on} = this.state;
        const children = React.Children.map(
            this.props.children,
            (child) => React.cloneElement(child, {
                on: this.state.on,
                toggle: this.toggle
            })
        );
        return (
            <div> {children} </div>
        )
      }

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  • 原文地址:https://www.cnblogs.com/Answer1215/p/8030709.html
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