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  • P1082

    //思路问题,可以把翻转N-1枚硬币转换为只翻转一枚硬币
    #include<iostream>
    using namespace std;
    int main()
    {
        int n;
        cin>>n;
        cout<<n<<endl;//找规律直接输出
        int coin[101];
        for(int i=1;i<=n;i++)
        {
            for(int j=1;j<=n;j++)
            {
                if(j!=i)
                {
                    if(coin[j]==1)
                    {
                        coin[j]=0;
                    }
                    else
                    {
                        coin[j]=1;
                    }
                }
                cout<<coin[j];
            }
            cout<<endl;
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/Chri-K/p/13640234.html
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