1 #include <cstdio> 2 #include <string> 3 #include <cstring> 4 #include <iostream> 5 using namespace std; 6 typedef long long ll; 7 ll num,k=10,ans;int t,calc,len;string str;char s[30]; 8 ll get10(){ 9 ans=0,scanf("%s",s+1),len=strlen(s+1); 10 for(int i=1;i<=len;i++)ans=ans*k+(s[i]>'9'?s[i]-'A'+10:s[i]-'0'); 11 return ans; 12 } 13 void print(ll x){if(x)print(x/k),putchar(x%k<=9?x%k+'0':x%k+'A'-10);} 14 void print(){if(num==0)putchar('0');else print(num);}//之前没考虑到答案为0 15 void oper(){ 16 cin>>str; 17 if(str=="CHANGE"){scanf("%lld",&k);return;} 18 if(str=="EQUAL"){print(),puts("");return;} 19 if(str=="CLEAR"){num=calc=0;return;} 20 if(str=="ADD"){calc=1;return;} 21 if(str=="SUB"){calc=2;return;} 22 if(str=="MUL"){calc=3;return;} 23 if(str=="DIV"){calc=4;return;} 24 if(str=="MOD"){calc=5;return;} 25 if(str=="NUM") 26 switch(calc){ 27 case 0:num+=get10();break;//这里意思是刚刚CLEAR过 28 case 1:num+=get10();break; 29 case 2:num-=get10();break; 30 case 3:num*=get10();break; 31 case 4:num/=get10();break; 32 case 5:num%=get10();break; 33 } 34 } 35 int main(){ 36 for(scanf("%d",&t);t--;)oper(); 37 return 0; 38 }