统计一个字符串中相同字符的个数

作为测试小白，苦练代码基本功，啥时候都不嫌晚。

今天在测试群里，看到小伙伴在面试中有个题目，用一段代码对一个字符串进行统计，分别输出字符与数量！！！

于是用业余时间写了下：

#!/usr/bin/env python
#  -*- coding:utf-8 -*-
message = "abcd12311aacc"
messagelist = []

def CountOfChar(message):
    for i in message:
        list1 = []
        for j in message:
            if i == j:
                list1.append(i)
        if list1 not in messagelist:
            messagelist.append(list1)
    for i in range(len(messagelist)):
        print (messagelist[i][0],len(messagelist[i]))

　　

方法二：

#!/usr/bin/env python
#  -*- coding:utf-8 -*-
message = "abcd12311aacc"
messagelist = []

def CountOfChar2(message):
    for msg in message:
        countmess = message.count(mes)
        msgstr = msg +":"+ str(countmess)
        if msgstr not in messagelist:
            messagelist.append(msgstr)
    for i in messagelist:
        print (i)

CountOfChar2(message)