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  • 打印两个有序链表的公共部分

    • 如果head1的值小于head2,则head1往下移动
    • 如果head2的值小于head1,则head2往下移动
    • 如果head1的值与head2的值相等,则打印这个值,然后head1与head2一起往下移动‘
    • head1或head2有任何一个移动到null,整个过程终止
    package chapter_2_listproblem;
    
    public class Problem_01_PrintCommonPart {
    
        public static class Node {
            public int value;
            public Node next;
            public Node(int data) {
                this.value = data;
            }
        }
    
        public static void printCommonPart(Node head1, Node head2) {
            System.out.print("Common Part: ");
            while (head1 != null && head2 != null) {
                if (head1.value < head2.value) {
                    head1 = head1.next;
                } else if (head1.value > head2.value) {
                    head2 = head2.next;
                } else {
                    System.out.print(head1.value + " ");
                    head1 = head1.next;
                    head2 = head2.next;
                }
            }
            System.out.println();
        }
    
        public static void printLinkedList(Node node) {
            System.out.print("Linked List: ");
            while (node != null) {
                System.out.print(node.value + " ");
                node = node.next;
            }
            System.out.println();
        }
    
        public static void main(String[] args) {
            Node node1 = new Node(2);
            node1.next = new Node(3);
            node1.next.next = new Node(5);
            node1.next.next.next = new Node(6);
    
            Node node2 = new Node(1);
            node2.next = new Node(2);
            node2.next.next = new Node(5);
            node2.next.next.next = new Node(7);
            node2.next.next.next.next = new Node(8);
    
            printLinkedList(node1);
            printLinkedList(node2);
            printCommonPart(node1, node2);
    
        }
    
    }
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  • 原文地址:https://www.cnblogs.com/chwy/p/5712520.html
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