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  • LeetCode 301. Remove Invalid Parentheses(DP)

    题目

    DP 险过。

    dp[i][j] :means it need remove at least dp[i][j] characters to get vaild parenthese from position i to postion j in string.
    vector str[i][j] store the parenthese string
    for example :
    "()())"
    dp[0][1]=0 vector[0][1]=["()"]
    dp[0][2]=1 vector[0][2]=["()"]
    dp[1][2]=0 vector[1][2]=["()"]
    dp[0][3]=0 vector[1][2]=["()()"]
    dp[0][4]=1 vector[0][4]=["()()","(())"]

    dp[0][4]=min(dp[0][1]+d[1][4],....dp[0][3]+dp[4][4],dp[1][3])

    class Solution {
    public:
        vector<string> str[1005][1005];
        int dp[1005][1005];
        
        vector<string> removeInvalidParentheses(string s) {
            
            if(s=="")
            {
                str[0][0].push_back("");
                return str[0][0];
            }
            
            for(int i=0;i<s.length();i++)
            {
                if(s[i]=='('||s[i]==')')
                {
                    dp[i][i] = 1;
                    str[i][i].push_back("");
                }
                else
                {
                    dp[i][i] = 0;
                    string ss;
                    ss+=s[i];
                    str[i][i].push_back(ss);
                }
            }
            
            for(int l=1;l<s.length();l++)
            {
                for(int i=0;i+l<s.length();i++)
                {
                    int j = i+l;
                    
                    dp[i][j]=INT_MAX;
                    
                    for(int k=i;k<j;k++)
                    {
                        if(dp[i][j]>=dp[i][k]+dp[k+1][j])
                        {
                            dp[i][j]=dp[i][k]+dp[k+1][j];
                            str[i][j].clear();
                            for(int p=0;p<str[i][k].size();p++)
                            {
                                for(int q=0;q<str[k+1][j].size();q++)
                                {
                                    string ss = str[i][k][p]+str[k+1][j][q];
                                    if(std::find(str[i][j].begin(), str[i][j].end(), ss) == str[i][j].end())
                                        str[i][j].push_back(ss);
                                }
                            }
                            
                        }
                    }
                    
                    if(s[i]=='('&&s[j]==')')
                    {
                        if(l==1)
                        {
                            dp[i][j]=0;
                            str[i][j].clear();
                            str[i][j].push_back("()");
                        }
                        else
                        {
                            if(dp[i][j]>=dp[i+1][j-1])
                            {
                                if(dp[i][j]>dp[i+1][j-1])
                                    str[i][j].clear();
                                
                                dp[i][j]=dp[i+1][j-1];
                                
                                for(int p=0;p<str[i+1][j-1].size();p++)
                                {
                                    string ss = s[i]+str[i+1][j-1][p]+s[j];
                                    if(std::find(str[i][j].begin(), str[i][j].end(), ss) == str[i][j].end())
                                        str[i][j].push_back(ss);
                                }
                            }
                            
                        
                        }
                    }
                    else
                    {
                        if(dp[i][j]>=dp[i+1][j-1]+2)
                        {
                            if(dp[i][j]>dp[i+1][j-1]+2)
                                str[i][j].clear();
                             dp[i][j]=dp[i+1][j-1]+2;
                            
                             for(int p=0;p<str[i+1][j-1].size();p++)
                             {
                                 string ss = str[i+1][j-1][p];
                                 if(std::find(str[i][j].begin(), str[i][j].end(), ss) == str[i][j].end())
                                        str[i][j].push_back(ss);
                                 
                             }
                        }
                    }
                }
            }
            
            return str[0][s.length()-1];
            
        }
    };
    
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  • 原文地址:https://www.cnblogs.com/dacc123/p/12433363.html
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