MySQL递归查询树状表的子节点、父节点

表结构和表数据就不公示了，查询的表user_role，主键是id，每条记录有parentid字段;

如下mysql查询函数即可实现根据一个节点查询所有的子节点，根据一个子节点查询所有的父节点。对于数据量较大的时候（我这里测试的1万条左右）。查询效率非常慢。建议在java代码中进行处理。

CREATE FUNCTION `getChildList`(rootId INT)
    RETURNS varchar(1000)
    BEGIN
      DECLARE sChildList VARCHAR(1000);
      DECLARE sChildTemp VARCHAR(1000);
      SET sChildTemp =cast(rootId as CHAR);
      WHILE sChildTemp is not null DO
        IF (sChildList is not null) THEN
          SET sChildList = concat(sChildList,',',sChildTemp);
    ELSE
      SET sChildList = concat(sChildTemp);
    END IF;
        SELECT group_concat(id) INTO sChildTemp FROM user_role where FIND_IN_SET(parentid,sChildTemp)>0;
      END WHILE;
      RETURN sChildList;
    END;
/*获取子节点*/
/*调用: 1、select getChildList(0) id; 
2、select * 5From user_role where FIND_IN_SET(id, getChildList(2));
*/
 
 
CREATE FUNCTION `getParentList`(rootId INT)
    RETURNS varchar(1000)
    BEGIN
      DECLARE sParentList varchar(1000);
      DECLARE sParentTemp varchar(1000);
      SET sParentTemp =cast(rootId as CHAR);
      WHILE sParentTemp is not null DO
    IF (sParentList is not null) THEN
         SET sParentList = concat(sParentTemp,',',sParentList);
    ELSE
     SET sParentList = concat(sParentTemp);
    END IF;
        SELECT group_concat(parentid) INTO sParentTemp FROM user_role where FIND_IN_SET(id,sParentTemp)>0;
      END WHILE;
      RETURN sParentList;
    END;
/*获取父节点*/
/*调用: 1、select getParentList(6) id; 
2、select * From user_role where FIND_IN_SET(id, getParentList(2));

*/