问题:
以↘️对角线为轴,折叠反转数组
Example 1: Input: [[1,2,3],[4,5,6],[7,8,9]] Output: [[1,4,7],[2,5,8],[3,6,9]] Example 2: Input: [[1,2,3],[4,5,6]] Output: [[1,4],[2,5],[3,6]] Note: 1 <= A.length <= 1000 1 <= A[0].length <= 1000
解法:
创建B数组行数和列数刚好和A相反。
赋值也是与A的i和j相反。
代码参考:
1 class Solution { 2 public: 3 vector<vector<int>> transpose(vector<vector<int>>& A) { 4 int i=0, j=0; 5 vector<vector<int>> B(A[0].size(),vector<int>(A.size(),0)); 6 for(i=0; i<A.size(); i++){ 7 for(j=0; j<A[0].size(); j++){ 8 B[j][i]=A[i][j]; 9 } 10 } 11 return B; 12 } 13 };