On the first row, we write a 0
. Now in every subsequent row, we look at the previous row and replace each occurrence of 0
with 01
, and each occurrence of 1
with 10
.
Given row N
and index K
, return the K
-th indexed symbol in row N
. (The values of K
are 1-indexed.) (1 indexed).
Examples: Input: N = 1, K = 1 Output: 0 Input: N = 2, K = 1 Output: 0 Input: N = 2, K = 2 Output: 1 Input: N = 4, K = 5 Output: 1 Explanation: row 1: 0 row 2: 01 row 3: 0110 row 4: 01101001
Note:
N
will be an integer in the range[1, 30]
.K
will be an integer in the range[1, 2^(N-1)]
.
思路:
递归即可,判断当前的k是奇数还是偶数,如果是偶数,那么再查看上一行是1还是0即可。k是奇数同理。
int kthGrammar(int N, int K) { if(N == 1) return 0; if(K % 2 == 0) return (kthGrammar(N - 1, K / 2) == 0) ? 1 : 0; else return (kthGrammar(N - 1, (K+1) / 2) == 0) ? 0 : 1; }