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  • js获取url参数值(转)

    方法一:正则分析法

     

    function getQueryString(name) {
    var reg =new RegExp("(^|&)"+ name +"=([^&]*)(&|$)", "i");
    var r = window.location.search.substr(1).match(reg);
    if (r !=null) return unescape(r[2]); returnnull;
    }

    这样调用:

    alert(GetQueryString("参数名1"));

    alert(GetQueryString(
    "参数名2"));

    alert(GetQueryString(
    "参数名3"));

    方法二:

    <span style="font-size: 16px;"><Script language="javascript">
    function GetRequest() {
       var url = location.search; //获取url中"?"符后的字串
       var theRequest = new Object();
       if (url.indexOf("?") != -1) {
          var str = url.substr(1);
          strs = str.split("&");
          for(var i = 0; i < strs.length; i ++) {
             theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);
          }
       }
       return theRequest;
    }
    </Script></span>

    这样调用:

    复制代码
    <Script language="javascript">
    var Request =new Object();
    Request
    = GetRequest();
    var 参数1,参数2,参数3,参数N;
    参数1
    = Request['参数1'];
    参数2
    = Request['参数2'];
    参数3
    = Request['参数3'];
    参数N
    = Request['参数N'];
    </Script>
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  • 原文地址:https://www.cnblogs.com/jinmingjie/p/2549969.html
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