Given a binary tree, return all root-to-leaf paths.
For example, given the following binary tree:
1 / 2 3 5
All root-to-leaf paths are:
["1->2->5", "1->3"]
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<string>ans; vector<string> binaryTreePaths(TreeNode* root) { if(root == NULL) return ans; string head = to_string(root->val); if(root->left) oneTreePath(head, root->left); if(root->right) oneTreePath(head, root->right); if(!root->left && !root->right) ans.push_back(head); return ans; } void oneTreePath(string head, TreeNode* root){ string newHead = head + "->" + to_string(root->val); if(root->left) oneTreePath(newHead, root->left); if(root->right) oneTreePath(newHead, root->right); if(!root->left && !root->right) ans.push_back(newHead); } };