（转）linux如何获取鼠标相对位置信息

[cpp] view plaincopy

 

#include <stdio.h>
#include <stdlib.h>
#include <linux/input.h>
#include <fcntl.h>
#include <sys/time.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <unistd.h>


int main(int argc,char **argv)
{
    int fd, retval;
    char buf[6];
    fd_set readfds;
    struct timeval tv;
    // 打开鼠标设备
    fd = open( "/dev/input/mice", O_RDONLY );
    // 判断是否打开成功
    if(fd<0) {
        printf("Failed to open "/dev/input/mice".
");
        exit(1);
    } else {
        printf("open "/dev/input/mice" successfuly.
");
    }

    while(1) {
        // 设置最长等待时间
        tv.tv_sec = 5;
        tv.tv_usec = 0;

        FD_ZERO( &readfds );
        FD_SET( fd, &readfds );

        retval = select( fd+1, &readfds, NULL, NULL, &tv );
        if(retval==0) {
            printf( "Time out!
" );
        }
        if(FD_ISSET(fd,&readfds)) {
            // 读取鼠标设备中的数据
            if(read(fd, buf, 6) <= 0) {
                continue;
            }
            // 打印出从鼠标设备中读取到的数据
            printf("Button type = %d, X = %d, Y = %d, Z = %d
", (buf[0] & 0x07), buf[1], buf[2],   buf[3]);
        }
    }
    close(fd);
    return 0;
}