zoukankan      html  css  js  c++  java
  • ural One-two, One-two 2

     One-two, One-two 2
    Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u
     
    Description
    A year ago the famous gangster Vito Maretti woke up in the morning and realized that he was bored of robbing banks of round sums. And for the last year he has been taking from banks sums that have only digits 1 and 2 in their decimal notation. After each robbery, Vito divides the money between N members of his gang. Your task is to determine the minimal stolen sum which is a multiple of N.

    Input

    The input contains the number N (1 ≤  N ≤ 10 6).

    Output

    Output the minimal number which is a multiple of N and whose decimal notation contains only digits 1 and 2. If it contains more than 30 digits or if there are no such numbers, then output "Impossible".

    Sample Input

    inputoutput
    5
    
    Impossible
    
    8
    
    112

    AC代码:

     1 #include<iostream>
     2 #include<cstring>
     3 #include<cstdio>
     4 #define N 5000002
     5 using namespace std;
     6 int n;         
     7 struct Node{
     8     int dig,mod;
     9     int f;//模拟指针,指向数组的下一个元素 
    10 }nod[N];
    11 
    12 int l,r;
    13 bool vis[N];
    14 int ret;
    15 
    16 void BFS(){
    17     while(l<r){
    18         int tmod1=(nod[l].mod*10+1)%n;
    19         int tmod2=(nod[l].mod*10+2)%n;
    20         if(!vis[tmod1]){
    21           vis[tmod1]=1;
    22             r++;
    23             nod[r].mod=tmod1;   
    24             nod[r].dig=1;
    25             nod[r].f=l;
    26             if(tmod1==0){ret=r;return ;}
    27         }
    28         if(!vis[tmod2]){
    29           vis[tmod2]=1;
    30             r++;
    31             nod[r].mod=tmod2;
    32             nod[r].dig=2;
    33             nod[r].f=l;
    34             if(tmod2==0){ret=r;return ;}
    35         }
    36 
    37         l++;
    38 
    39     }
    40 }
    41 
    42 void out(int x)
    43 {
    44     if(x>0)out(nod[x].f);
    45     else if(x==0)return;
    46     cout<<nod[x].dig;
    47 }
    48 
    49 void first()
    50 {
    51    nod[1].dig=1;
    52    nod[1].f=0;
    53    nod[1].mod=1;
    54    nod[2].dig=2;
    55    nod[2].f=0;
    56    nod[2].mod=2;
    57 }
    58 
    59 int main()
    60 {
    61     while(cin>>n)
    62     {
    63         if(n==1||n==2){
    64             cout<<n<<endl;
    65             continue;
    66         }
    67         first();
    68         
    69         l=1;r=2;ret=0;
    70         memset(vis,0,sizeof(vis));
    71         vis[1]=vis[2]=1;
    72        
    73         BFS();
    74         if(ret==0){
    75             cout<<"Impossible"<<endl;
    76             continue;
    77         }
    78         out(ret);
    79         cout<<endl;
    80     }
    81     return 0;
    82 }
  • 相关阅读:
    Centos7下安装Oracle11g r2图形化界面数据库
    power designer 16.5 使用总结[转]
    mybatis-plus忽略映射字段
    mybatis-plus快速入门使用
    git本地项目代码上传至码云远程仓库总结【转】
    北京Java笔试题整理
    linux下启动和关闭tomcat服务的方式
    SpringMvc支持跨域访问,Spring跨域访问,SpringMvc @CrossOrigin 跨域[转]
    mybatis中的#和$的区别
    Spring官网下载dist.zip的几种方法
  • 原文地址:https://www.cnblogs.com/liugl7/p/4843423.html
Copyright © 2011-2022 走看看