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  • POJ 3440 Coin Toss(求概率)

    题目链接

    题意 :把硬币往棋盘上扔,分别求出硬币占1,2,3,4个格子的时候的概率。

    思路 : 求出公式输出,不过要注意输出格式,我还因为输入的时候用了int类型错了好几次。。。。。

     1 //3440
     2 #include <stdio.h>
     3 #include <string.h>
     4 #include <iostream>
     5 #include <math.h>
     6 #define PI acos(-1.0)
     7 
     8 using namespace std ;
     9 
    10 int main()
    11 {
    12     int k;
    13     double a1,a2,a3,a4,sum;
    14     double c,m,n,t;
    15     scanf("%d",&k) ;
    16     for(int i = 1 ; i <= k ; i++){
    17        scanf("%lf %lf %lf %lf",&m,&n,&t,&c) ;
    18         sum = m*n*t*t;
    19         a1 = (t-c)*(t-c)*n*m+(c*(t-c)+c*c/4.0)*4+c*(t-c)*(n+m-4) ;
    20         a2 = (m-1)*n*t*c+(n-1)*m*t*c-2*(m-1)*(n-1)*c*c;
    21         a3 = (m-1)*(n-1)*c*c*(1-PI/4);
    22         a4 = (m-1)*(n-1)*c*c*PI/4;
    23         printf("Case %d:
    ",i);
    24         printf("Probability of covering 1 tile  = %.4f%%
    ",100*a1/sum);
    25         printf("Probability of covering 2 tiles = %.4f%%
    ",100*a2/sum);
    26         printf("Probability of covering 3 tiles = %.4f%%
    ",100*a3/sum);
    27         printf("Probability of covering 4 tiles = %.4f%%
    ",100*a4/sum);
    28         printf("
    ");
    29     }
    30     return 0 ;
    31 }
    View Code
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  • 原文地址:https://www.cnblogs.com/luyingfeng/p/3784058.html
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