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  • USACO 2.4 Bessie Come Home

    mark:就是个最短路。。。错了2次,一次是题目没读清楚,一次是自己犯2。。。

    代码:

     1 # include <stdio.h>
     2 
     3 
     4 int graph[210][210] ;
     5 int INF = 0x0f0f0f0f ;
     6 
     7 
     8 int min(int a, int b){return a<b?a:b;}
     9 
    10 
    11 int main ()
    12 {
    13     char ch1, ch2 ;
    14     int num, p, pos, i, j, k ;
    15     
    16     freopen ("comehome.in", "r", stdin) ;
    17     freopen ("comehome.out", "w", stdout) ;
    18     
    19     while (~scanf ("%d%*c", &p))
    20     {
    21         for (i = 0 ; i < 200 ; i++)
    22         {
    23             for (j = 0 ; j < 200 ; j++)
    24                 if (i != j) graph[i][j] = INF ;
    25                 else graph[i][j] = 0 ;
    26         }
    27         while (p--)
    28             scanf ("%c %c %d%*c", &ch1, &ch2, &num),
    29             graph[ch1][ch2] = graph[ch2][ch1] = min(graph[ch1][ch2], num) ;
    30         
    31         for (k = 0 ; k <= 'z' ; k++)
    32             for (i = 0 ; i <= 'z' ; i++)
    33                 for (j = 0 ; j <= 'z' ; j++)
    34                     if (graph[i][k]+graph[k][j] < graph[i][j])
    35                         graph[i][j] = graph[i][k]+graph[k][j] ;
    36         pos = -1 ;
    37         for (i = 'A' ; i < 'Z' ; i++)
    38             if (pos == -1 || graph[i]['Z'] < graph[pos]['Z']) pos = i ;
    39         printf ("%c %d
    ", pos, graph[pos]['Z']) ;
    40     }
    41     return 0 ;
    42 }
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  • 原文地址:https://www.cnblogs.com/lzsz1212/p/3170771.html
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