Bubble Sort
Write a program of the Bubble Sort algorithm which sorts a sequence A in ascending order. The algorithm should be based on the following pseudocode:
BubbleSort(A) 1 for i = 0 to A.length-1 2 for j = A.length-1 downto i+1 3 if A[j] < A[j-1] 4 swap A[j] and A[j-1]
Note that, indices for array elements are based on 0-origin.
Your program should also print the number of swap operations defined in line 4 of the pseudocode.
Input
The first line of the input includes an integer N, the number of elements in the sequence.
In the second line, N elements of the sequence are given separated by spaces characters.
Output
The output consists of 2 lines.
In the first line, please print the sorted sequence. Two contiguous elements of the sequence should be separated by a space character.
In the second line, please print the number of swap operations.
Constraints
1 ≤ N ≤ 100
Sample Input 1
5 5 3 2 4 1
Sample Output 1
1 2 3 4 5 8
Sample Input 2
6 5 2 4 6 1 3
Sample Output 2
1 2 3 4 5 6 9
#include <iostream> #include <algorithm> using namespace std; const int MAX = 110; int a[MAX]; int sum; void BubbleSort(int a[], int n) { for(int i = 0; i < n - 1; ++ i) { for(int j = n - 1; j >= i + 1; -- j) { if(a[j] < a[j - 1]) { swap(a[j], a[j - 1]); sum ++; } } } }
//void BubbleSort(int a[], int n) //{ // int flag = 1; // 存在顺序相反的相邻元素 // for(int i = 0; flag; ++ i) // { // flag = 0; // for(int j = n - 1; j > i; -- j) // { // if(a[j] < a[j - 1]) // { // swap(a[j], a[j - 1]); // flag = 1; // sum ++; // } // } // } //}
int main() { int n; cin >> n; for(int i = 0; i < n; ++ i) { cin >> a[i]; } BubbleSort(a, n); for(int i = 0; i < n; ++ i) { if(i == n - 1) cout << a[i]; else cout << a[i] << " "; } cout << endl; cout << sum << endl; return 0; }